A353732 Inverse permutation to A352808: a(n) = index where n appears in A352808.

0, 1, 2, 6, 3, 4, 10, 11, 5, 7, 8, 18, 12, 19, 32, 44, 9, 16, 14, 24, 13, 17, 15, 45, 20, 21, 50, 56, 51, 52, 62, 63, 22, 25, 26, 27, 28, 29, 33, 40, 23, 30, 34, 78, 48, 70, 79, 122, 36, 64, 38, 84, 37, 71, 82, 98, 83, 85, 94, 123, 92, 148, 134, 210, 31, 41, 35, 46, 42, 47, 43, 72, 49, 53, 57, 73, 54, 76, 128, 162, 39, 65, 58, 96, 55, 68, 60

Offset: 0

Author

N. J. A. Sloane, May 17 2022

Keywords

• nonn

Links

• Michael S. Branicky, Table of n, a(n) for n = 0..10000

Crossrefs

Cf. A353808, A353731.

Programs

Python

from itertools import count, islice
def agen(): # generator of terms
    A352808lst = [0, 1]; A352808set = {0, 1}; yield from [0, 1]
    mink = 2
    for n in count(2):
        ahalf, k = A352808lst[n//2], mink
        while k in A352808set or k&ahalf: k += 1
        A352808lst.append(k); A352808set.add(k)
        while mink in A352808set: yield A352808lst.index(mink); mink += 1
print(list(islice(agen(), 87))) # Michael S. Branicky, May 17 2022