A353735 Number of n-digit terms in A333369.
5, 24, 130, 792, 5080, 34584, 247360, 1817112, 13918720, 108848664, 869866240, 7169995032, 59085276160, 505735077144, 4311229112320, 37428004374552, 335520388710400, 2861870689152024, 27669446179225600, 223578655251963672, 2398913308953149440, 17708639883984065304
Offset: 1
Examples
There are five 1-digit terms in A333369: 1, 3, 5, 7, 9. Thus, a(1) = 5.
Links
- Michael S. Branicky, Table of n, a(n) for n = 1..1002
- Project Euler, Problem 520: Simbers.
Programs
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Python
def isA333369(n): digits = list(map(int, str(n))) return all(digits.count(d)%2 == d%2 for d in set(digits)) def a(n): return sum(1 for i in range(10**(n-1), 10**n) if isA333369(i)) print([a(n) for n in range(1, 7)]) # Michael S. Branicky, May 06 2022
Formula
From Bernard Schott, Jul 11 2022: (Start)
Conjecture 1: lim_{n->oo} a(2n+1)/a(2n-1) = 100.
Conjecture 2: lim_{n->oo} a(2n+2)/a(2n) = 81. (End)
Comments