cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A353769 Decimal expansion of the gravitational acceleration generated at the center of a face by a unit-mass cube with edge length 2 in units where the gravitational constant is G = 1.

Original entry on oeis.org

6, 4, 9, 2, 2, 4, 1, 4, 4, 5, 6, 4, 5, 9, 1, 2, 6, 4, 7, 1, 2, 4, 7, 4, 7, 4, 2, 4, 4, 6, 6, 8, 2, 0, 3, 1, 5, 3, 5, 9, 5, 0, 1, 6, 4, 6, 9, 1, 0, 4, 1, 9, 3, 1, 3, 4, 8, 7, 8, 0, 0, 3, 3, 4, 0, 3, 3, 2, 2, 1, 2, 8, 6, 1, 7, 1, 1, 1, 5, 9, 9, 4, 3, 1, 3, 1, 4, 4, 2, 9, 8, 3, 8, 6, 5, 2, 6, 4, 0, 8, 2, 9, 9, 0, 0
Offset: 0

Views

Author

Amiram Eldar, May 07 2022

Keywords

Comments

The absolute value of the gravitational attraction force between a homogeneous cube with mass M and edge length 2*s and a test particle with mass m located at the cube's center of face is c*G*M*m/s^2, where G is the gravitational constant (A070058) and c is this constant.
The centers of the faces are the positions where the gravitational field that is generated by the cube attains its maximum absolute value.

Examples

			0.64922414456459126471247474244668203153595016469104...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Pi/2 + Log[(Sqrt[2] + 1)*(Sqrt[6] - 1)/Sqrt[5]] - 2*ArcSin[Sqrt[2/5]], 10, 100][[1]]

Formula

Equals Pi/2 + log((sqrt(2) + 1)*(sqrt(6) - 1)/sqrt(5)) - 2*arcsin(sqrt(2/5)).

A353770 Decimal expansion of the gravitational acceleration generated at a vertex by a unit-mass cube with edge length 2 in units where the gravitational constant is G = 1.

Original entry on oeis.org

4, 1, 9, 7, 5, 7, 3, 3, 9, 8, 8, 7, 1, 0, 6, 2, 9, 1, 8, 7, 3, 7, 4, 7, 6, 8, 7, 2, 0, 0, 8, 1, 3, 9, 0, 9, 6, 0, 5, 8, 5, 6, 1, 0, 2, 7, 6, 1, 7, 7, 2, 6, 6, 1, 3, 8, 7, 8, 2, 7, 5, 6, 1, 7, 1, 2, 7, 6, 5, 7, 4, 5, 1, 0, 4, 7, 7, 6, 7, 5, 7, 6, 6, 1, 4, 8, 8, 7, 0, 3, 0, 2, 5, 9, 9, 8, 8, 7, 0, 6, 4, 5, 9, 7, 1
Offset: 0

Views

Author

Amiram Eldar, May 07 2022

Keywords

Comments

The absolute value of the gravitational attraction force between a homogeneous cube with mass M and edge length 2*s and a test particle with mass m located at the cube's vertex is c*G*M*m/s^2, where G is the gravitational constant (A070058) and c is this constant.
The vertices are the positions where the gravitational field that is generated by the cube on its surface attains its minimum absolute value.

Examples

			0.41975733988710629187374768720081390960585610276177...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[(Sqrt[3]/2)*(Pi/12 + Log[Sqrt[2] + 1] - Log[Sqrt[3] + 2]/2), 10, 100][[1]]

Formula

Equals (sqrt(3)/2)*(Pi/12 + log(sqrt(2) + 1) - log(sqrt(3) + 2)/2).

A353772 Decimal expansion of the gravitational acceleration generated at a vertex by a unit-mass regular tetrahedron with edge length 2 in units where the gravitational constant is G = 1.

Original entry on oeis.org

9, 5, 4, 8, 5, 4, 6, 6, 5, 9, 6, 6, 1, 5, 6, 7, 8, 0, 1, 4, 5, 5, 0, 9, 5, 2, 8, 0, 3, 3, 6, 9, 0, 5, 8, 9, 6, 0, 2, 4, 7, 1, 4, 7, 0, 9, 8, 7, 5, 7, 2, 3, 4, 0, 9, 8, 0, 2, 0, 0, 8, 3, 5, 1, 3, 3, 4, 2, 7, 0, 0, 4, 5, 7, 9, 9, 0, 5, 9, 5, 5, 1, 3, 2, 1, 0, 3, 7, 3, 5, 2, 7, 7, 0, 0, 1, 0, 4, 7, 9, 0, 6, 2, 6, 2
Offset: 0

Views

Author

Amiram Eldar, May 07 2022

Keywords

Comments

The absolute value of the gravitational attraction force between a homogeneous regular tetrahedron with mass M and edge length 2*s and a test particle with mass m located at the tetrahedron's vertex is c*G*M*m/s^2, where G is the gravitational constant (A070058) and c is this constant.
The vertices are the positions where the gravitational field that is generated by the tetrahedron on its surface attains its minimum absolute value.

Examples

			0.95485466596615678014550952803369058960247147098757...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[6*Sqrt[3]*(Pi/3 - ArcTan[Sqrt[2]]), 10, 100][[1]]

Formula

Equals 6*sqrt(3)*(Pi/3 - arctan(sqrt(2))).
Equals 3*sqrt(3)*(Pi/6 - arctan(sqrt(2)/4)).

A353773 Decimal expansion of the gravitational acceleration generated at a vertex by a unit-mass regular octahedron with edge length 2 in units where the gravitational constant is G = 1.

Original entry on oeis.org

6, 4, 7, 0, 5, 8, 8, 2, 7, 5, 9, 7, 8, 4, 7, 3, 5, 8, 2, 3, 7, 9, 0, 6, 1, 9, 4, 7, 4, 6, 1, 7, 4, 6, 6, 8, 5, 4, 7, 7, 4, 2, 9, 8, 0, 4, 6, 7, 8, 6, 6, 8, 1, 4, 6, 7, 8, 0, 1, 1, 8, 3, 1, 5, 5, 4, 1, 6, 2, 6, 2, 7, 5, 5, 0, 0, 0, 9, 4, 1, 3, 7, 3, 1, 6, 0, 7, 7, 7, 9, 2, 6, 2, 3, 0, 1, 8, 8, 4, 7, 6, 7, 8, 3, 1
Offset: 0

Views

Author

Amiram Eldar, May 07 2022

Keywords

Comments

The absolute value of the gravitational attraction force between a homogeneous regular octahedron with mass M and edge length 2*s and a test particle with mass m located at the octahedron's vertex is c*G*M*m/s^2, where G is the gravitational constant (A070058) and c is this constant.
The vertices are the positions where the gravitational field that is generated by the octahedron on its surface attains its minimum absolute value.

Examples

			0.64705882759784735823790619474617466854774298046786...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Sqrt[2]*Log[3*(Sqrt[2]-1)] + ArcTan[Sqrt[2]/4], 10, 100][[1]]

Formula

Equals sqrt(2)*log(3*(sqrt(2)-1)) + arctan(sqrt(2)/4).
Showing 1-4 of 4 results.