A354526 Numbers k such that A354512(k) < omega(k); complement of A354525.
4, 8, 10, 12, 16, 18, 20, 22, 24, 26, 27, 28, 30, 32, 34, 36, 38, 39, 40, 42, 44, 46, 48, 50, 52, 54, 56, 57, 58, 60, 63, 64, 65, 66, 68, 70, 72, 74, 75, 76, 78, 80, 81, 82, 84, 86, 87, 88, 90, 92, 94, 96, 98, 99, 100, 102, 104, 105, 106, 108, 110, 111, 112, 114, 116, 117
Offset: 1
Examples
57 is a term since the prime factors of 57 are 3,19, and we have gpf(57+3) != 3.
Links
- Jianing Song, Table of n, a(n) for n = 1..7946 (all terms <= 10000)
Programs
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PARI
gpf(n) = vecmax(factor(n)[, 1]); isA354526(n) = my(f=factor(n)[, 1]); for(i=1, #f, if(gpf(n+f[i])!=f[i], return(1))); 0
Comments