A354667 Triangle read by rows: T(n,k) is the number of tilings of an (n+4*k) X 1 board using k (1,1;5)-combs and n-k squares.
1, 1, 0, 1, 0, 1, 1, 0, 2, 0, 1, 0, 4, 0, 1, 1, 1, 6, 0, 3, 0, 1, 2, 9, 0, 9, 0, 1, 1, 3, 12, 5, 18, 0, 4, 0, 1, 4, 16, 12, 36, 0, 16, 0, 1, 1, 5, 20, 25, 60, 15, 40, 0, 5, 0, 1, 6, 25, 42, 100, 42, 100, 0, 25, 0, 1, 1, 7, 31, 66, 150, 112, 200
Offset: 0
Examples
Triangle begins: 1; 1, 0; 1, 0, 1; 1, 0, 2, 0; 1, 0, 4, 0, 1; 1, 1, 6, 0, 3, 0; 1, 2, 9, 0, 9, 0, 1; 1, 3, 12, 5, 18, 0, 4, 0; 1, 4, 16, 12, 36, 0, 16, 0, 1; 1, 5, 20, 25, 60, 15, 40, 0, 5, 0; 1, 6, 25, 42, 100, 42, 100, 0, 25, 0, 1; 1, 7, 31, 66, 150, 112, 200, 35, 75, 0, 6, 0; ...
Links
- Michael A. Allen, On a Two-Parameter Family of Generalizations of Pascal's Triangle, arXiv:2209.01377 [math.CO], 2022.
- Michael A. Allen, On A Two-Parameter Family of Generalizations of Pascal's Triangle, J. Int. Seq. 25 (2022) Article 22.9.8.
Crossrefs
Programs
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Mathematica
T[n_,k_]:=If[k<0 || n
Formula
T(n,k) = T(n-1,k) + T(n-1,k-1) - T(n-2,k-1) + 2*T(n-2,k-2) + T(n-3,k-1) - T(n-3,k-2) - 2*T(n-3,k-3) - T(n-4,k-1) + T(n-4,k-2) + T(n-4,k-3) - T(n-4,k-4) + T(n-5,k-1) - 2*T(n-5,k-3) + T(n-5,k-5) + delta(n,0)*delta(k,0) - delta(n,1)*delta(k,1) - delta(n,2)*delta(k,2) - delta(n,3)*(delta(k,1) - delta(k,3)) with T(n,k<0) = T(n
T(n,0) = 1.
T(n,n) = delta(n mod 2,0).
T(n,1) = n-4 for n>3.
T(2*j+r,2*j-1) = 0 for j>0, r=-1,0,1,2.
T(n,2*j) = C(n/2,j)^2 for j>0 and n even and 2*j <= n <= 2*j+8.
T(n,2*j) = C((n-1)/2,j)*C((n+1)/2,j) for j>0 and n odd and 2*j < n < 2*j+8.
T(2*j+3*p,2*j-p) = C(j+3,4)^p for j>0 and p=0,1,2.
G.f. of row sums: (1-x-x^2)/(1-2*x-x^2+2*x^3).
G.f. of sums of T(n-4*k,k) over k: (1-x^5-x^7-x^10+x^15)/(1-x-x^5+x^6-x^7+x^8-x^9-2*x^10+x^11-x^12+2*x^15-x^16+2*x^17+x^20-x^25).
T(n,k) = T(n-1,k) + T(n-1,k-1) for n>=4*k+1 if k>=0.
Comments