A355278 Lower left of the Cayley table for the primes when made into a group using the bijection (2, 3, 5, 7, ...) -> (0, +1, -1, +2, ...) into (Z, +); read by rows.
2, 3, 7, 5, 2, 11, 7, 13, 3, 19, 11, 5, 17, 2, 23, 13, 19, 7, 29, 3, 37, 17, 11, 23, 5, 31, 2, 41, 19, 29, 13, 37, 7, 43, 3, 53, 23, 17, 31, 11, 41, 5, 47, 2, 59, 29, 37, 19, 43, 13, 53, 7, 61, 3, 71, 31, 23, 41, 17, 47, 11, 59, 5, 67, 2, 73, 37, 43, 29
Offset: 1
Examples
The correspondence of primes p with integers m is as follows: p | 2 | 3 | 5 | 7 | 11 | 13 | 17 | 19 | 23 | 29 | 31 | ... ---+----+----+----+----+----+----+----+----+----+----+----+---- m | 0 | 1 | -1 | 2 | -2 | 3 | -3 | 4 | -4 | 5 | -5 | ... The table of the abelian group (P, *) based on this correspondence with (Z, +) starts as follows: [ 2 3 5 7 11 13 17 ...] [ 3 7 2 13 5 19 11 ...] [ 5 2 11 3 17 7 23 ...] [ 7 13 3 19 2 29 5 ...] [11 5 17 2 23 3 31 ...] [13 19 7 29 3 37 2 ...] [17 11 23 5 31 2 41 ...] [... ... ... ...] This means that 3 * 3 = 7, 3 * 5 = 2, 3 * 7 = 13, etc.: for example, primes 3 and 7 are associated to integers 1 and 2, so 3 * 7 is the prime associated to the integer 1 + 2 = 3, which yields 13. Since 2, associated to 0 in Z, is the neutral element in the group (P, *), the first row and column is identical to the list of the primes themselves. Therefore we do not need to show row and columns headings in addition to the first row & column of the body of the table. Since the table is symmetric, T(m,n) = T(n,m) <=> p * q = q * p, the sequence lists only the lower left part: 2; 3, 7; 5, 2, 11; 7, 13, 3, 19; ... The list of inverses of the primes 2, 3, 5, 7, 11, ... with respect to this group operation is 2, 5, 3, 11, 7, 17, 13, ... = A000040(A065190(n)), i.e., after the initial 2, list the primes with the two members of each subsequent pair swapped: swap 3 and 5, 7 and 11, 13 and 17, etc.
Links
- Antonio (u/hilberts12th), An example of a binary operation * such that (Set of prime numbers, *) is a group?, in r/abstractalgebra on reddit.com, May 18 2022
Programs
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PARI
A355278(m,n) = inv(f(prime(m))+f(prime(n))) inv(x, p)=while(!mapisdefined(INV,x,&p), mapput(INV, f(p=prime(#INV+1)), p)); p INV=Map(); f(p)=(p=primepi(p))\2*(-1)^(p%2)
Comments