cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A356977 a(n) is the number of solutions, j >= 0 and 2 <= m_1 <= ... <= m_n, of the equation Sum_{k=1..n} F(m_k) = 2^j where F(i) is the i-th Fibonacci number.

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%I A356977 #10 Nov 01 2022 13:48:24
%S A356977 0,3,6,10,36,66
%N A356977 a(n) is the number of solutions, j >= 0 and 2 <= m_1 <= ... <= m_n, of the equation Sum_{k=1..n} F(m_k) = 2^j where F(i) is the i-th Fibonacci number.
%C A356977 The difficulty of this sequence comes in determining which is the largest j in a solution for a(n), equivalently the last nonzero term in each sum from the A319394-based formula in the formula section.
%C A356977 a(2) derives from Bravo and Luca, a(3) from Bravo and Bravo, a(4) from Pagdame Tiebekabe and Diouf. Pagdame has indicated A356928(5), from which a(5) is derived, has been determined.
%C A356977 a(6) >= 178, a(7) >= 478.
%D A356977 J. J. Bravo, and F. Luca, On the Diophantine equation F_n+F_m=2^a, Quaest. Math. 39 (2016) 391-400.
%D A356977 P. Tiebekabe and I. Diouf, On solutions of Diophantine equation F_{n_1}+F_{n_2}+F_{n_3}+F_{n_4}=2^a, Journal of Algebra and Related Topics, Volume 9, Issue 2 (2021), 131-148.
%H A356977 E. F. Bravo and J. J. Bravo, <a href="https://www.researchgate.net/publication/282537969_Powers_of_two_as_sums_of_three_Fibonacci_numbers">Powers of two as sums of three Fibonacci numbers</a>, Lithuanian Mathematical Journal, 55, pp. 301-311 (2015).
%F A356977 a(n) = Sum_{i >= 0} A319394(2^i, k).
%e A356977 For n = 2, the a(2) = 6 solutions are j = 1 with (2,2), j = 2 with (2,4) and (3,3), j = 3 with (4,5), j = 4 with (4,7) and (6,6) according to the paper of Bravo and Luca. [That is, 2 = 1+1, 4 = 1+3 = 2+2, 8 = 3+5, 16 = 3+13 = 8+8.]
%Y A356977 Cf. A020908, A319394, A356928.
%K A356977 nonn,hard,more
%O A356977 0,2
%A A356977 _Peter Munn_ and _Jon E. Schoenfield_, Sep 07 2022