A357629 Half-alternating sum of the prime indices of n.
0, 1, 2, 2, 3, 3, 4, 1, 4, 4, 5, 0, 6, 5, 5, 0, 7, 1, 8, -1, 6, 6, 9, -1, 6, 7, 2, -2, 10, 0, 11, 1, 7, 8, 7, -2, 12, 9, 8, -2, 13, -1, 14, -3, 1, 10, 15, 2, 8, 1, 9, -4, 16, -1, 8, -3, 10, 11, 17, -3, 18, 12, 0, 2, 9, -2, 19, -5, 11, 0, 20, 1, 21, 13, 2, -6
Offset: 1
Keywords
Examples
The prime indices of 525 are {2,3,3,4} so a(525) = 2 + 3 - 3 - 4 = -2.
Crossrefs
The reverse version is A357633.
Programs
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Mathematica
primeMS[n_]:=If[n==1,{},Flatten[Cases[FactorInteger[n],{p_,k_}:>Table[PrimePi[p],{k}]]]]; halfats[f_]:=Sum[f[[i]]*(-1)^(1+Ceiling[i/2]),{i,Length[f]}]; Table[halfats[primeMS[n]],{n,30}]
Comments