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A357923 a(n) is the least number of terms in the sum S = 1/(n+1) + 1/(n+2) + 1/(n+3) + ... such that S > n.

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%I A357923 #23 Dec 12 2022 22:30:30
%S A357923 1,3,17,68,242,812,2619,8224,25345,77006,231355,688758,2034965,
%T A357923 5973932,17441201,50678536,146643235,422769139,1214857227,3480786068,
%U A357923 9946872233,28357093263,80667175724,229020154166,649028530125,1836242560272,5187142333288,14632132586005
%N A357923 a(n) is the least number of terms in the sum S = 1/(n+1) + 1/(n+2) + 1/(n+3) + ... such that S > n.
%F A357923 From _Thomas Scheuerle_, Nov 30 2022: (Start)
%F A357923 a(n) ~ ceiling(exp(n + digamma(1+n)) - (1/2) - n).
%F A357923 floor(digamma(a(n)+n+1) - digamma(n+1)) = n. (End)
%e A357923 For n=0, a single term suffices: S = 1/1 > n = 0.
%e A357923 For n=1, a(1) = 3 terms suffice: S = 1/2 + 1/3 + 1/4 > n = 1.
%e A357923 For n=2, a(3) = 17 terms suffice: S = 1/3 + ... + 1/19 > 2.
%Y A357923 Cf. A002387, A358464.
%K A357923 nonn
%O A357923 0,2
%A A357923 _Gil Broussard_, Oct 20 2022
%E A357923 a(18)-a(27) from _Jon E. Schoenfield_, Nov 30 2022