cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A357992 a(1)=1,a(2)=2,a(3)=3. Thereafter, if there are prime divisors p of a(n-2) which do not divide a(n-1), a(n) is the least novel multiple of any such p. Otherwise a(n) is the least novel multiple of the squarefree kernel of a(n-2).

Original entry on oeis.org

1, 2, 3, 4, 6, 8, 9, 10, 12, 5, 14, 15, 7, 18, 21, 16, 24, 20, 27, 22, 30, 11, 25, 33, 35, 36, 28, 39, 26, 42, 13, 32, 52, 34, 65, 17, 40, 51, 38, 45, 19, 48, 57, 44, 54, 55, 46, 50, 23, 56, 69, 49, 60, 63, 58, 66, 29, 62, 87, 31, 72, 93, 64, 75, 68, 70, 85, 74
Offset: 1

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Author

David James Sycamore, Oct 23 2022

Keywords

Comments

In other words, if a(n-2) has k prime divisors p_j; 1 <= j <= k which do not divide a(n-1), where 1 <= k <= omega(a(n-2)), and if m_j*p_j is the least multiple of p_j which is not already a term, then a(n) = Min{m_j*p_j; 1 <= j <= k}. Otherwise, every prime divisor of a(n-2) also divides a(n-1), in which case a(n) is the least multiple of the squarefree kernel of a(n-2) which is not already a term.
Unlike in A064413, a prime p occurrence here is not directly flanked by multiples of p, but by numbers x, y sharing divisors other than p. The terms preceding and following x and y are divisible by p. Typically we observe m*p, x, p, y, r*p, where gcd(x, y) > 1, for multiples m,r of p which do not always follow the (2,3) pattern observed in A064413 and elsewhere. The case of p = 13 is remarkable for being preceded and followed by two multiples of itself (the first five multiples of 13 occur within the span of eight consecutive terms).
Conjecture 1: A permutation of the positive integers with primes in natural order.
Conjecture 2: The primes are the slowest numbers to appear (see also A352187).

Examples

			With a(2)=2, and a(3)=3, a(4) must be 4, the least unused multiple of 2.
Likewise, with a(3),a(4) = 3,4 a(5) must be the 6, the least unused multiple of 3.
Since every divisor of 4 also divides 6 a(6) = 8, the least unused multiple of 2, (squarefree kernel of 4).
Since a(8),a(9) = 10,12 and 5 is the only prime dividing 10 but not 12, it follows that a(10) = 5.
		

Crossrefs

Programs

  • Mathematica
    Block[{a, c, f, g, k, m, q, nn}, nn = 68; c[] = False; q[] = 1; Array[Set[{a[#], c[#]}, {#, True}] &, 2]; q[2] = 2; Do[m = FactorInteger[a[n - 2]][[All, 1]]; f = Select[m, CoprimeQ[#, a[n - 1]] &]; If[Length[f] == 0, While[Set[k, #* q[#]]; c[k], q[#]++] &[Times @@ m], Set[{k, q[#1]}, {#2, #2/#1}] & @@ First@ MinimalBy[Map[{#, Set[g, q[#]]; While[c[g #], g++]; # g} &, f], Last]]; Set[{a[n], c[k]}, {k, True}], {n, 3, nn}]; Array[a, nn]] (* Michael De Vlieger, Oct 23 2022 *)

Extensions

More terms from Michael De Vlieger, Oct 23 2022