A358874 Inverse permutation to A076034.
1, 2, 3, 4, 5, 7, 6, 11, 12, 16, 8, 22, 9, 29, 30, 37, 10, 46, 13, 56, 17, 67, 14, 79, 15, 92, 38, 106, 18, 121, 19, 137, 57, 154, 23, 172, 20, 191, 68, 211, 21, 232, 24, 254, 93, 277, 25, 301, 39, 326, 107, 352, 26, 379, 40, 407, 138, 436, 27, 466, 28, 497
Offset: 1
Examples
A076034(42) = 101, so a(101) = 42.
Links
Programs
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Maple
S:=[$1..10000]: V:= Vector(10000): ok:= true; for n from 1 while ok do A:= [S[1]]; R:= 1; count:= 1; for k from 2 while count < n do if k > nops(S) then ok:= false; break fi; if andmap(t -> igcd(t,S[k])=1, A) then count:= count+1; A:= [op(A),S[k]]; R:= R,k; fi od; S:= subsop(op(map(t -> t=NULL, [R])),S); for i from 1 to nops(A) do V[A[i]]:= n*(n-1)/2+i od od: if member(0,V,'q') then convert(V[1..q-1],list) else convert(V,list) fi; # Robert Israel, Dec 04 2022
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PARI
See Links section.
Formula
a(2*n) = A000124(n).
a(p) < a(n) if p < n with p a prime number.