A359500 a(n) = (7^2^n - 1)/2^(n+3).
3, 75, 90075, 259632270075, 4314170602515315024630075, 2382344702413741601833152075318304337413311121350075, 1452944967966417671787414728262962471027692106596483349510252251060925112718067382475349181570930962790075
Offset: 1
Links
- Jianing Song, Table of n, a(n) for n = 1..10
Crossrefs
Programs
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PARI
a(n) = (7^2^n - 1)/2^(n+3)
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Python
def A359500(n): return 7**(1<
>n+3 # Chai Wah Wu, Jan 15 2023
Formula
a(n)/a(n-1) = (7^2^(n-1) + 1)/2 = 2^(n+1) * a(n-1) + 1.
For all n > m, a(n) and a(m) are congruent modulo 2^(m+2) but not modulo 2^(m+3).