This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A359919 #16 Jan 05 2024 17:17:35
%S A359919 1,0,1,5,19,65,211,681,2255,7830,28786,111230,443789,1795972,7284981,
%T A359919 29466755,118834438,479034654,1936617163,7872885832,32226147305,
%U A359919 132808096158,550444192577,2291095125465,9564074472264,40005894288101,167610376198140,703308153554903
%N A359919 a(n) = coefficient of x^n in A(x) such that x^2 = Sum_{n=-oo..+oo} x^(n*(3*n+1)/2) * (A(x)^(3*n) - 1/A(x)^(3*n+1)).
%H A359919 Paul D. Hanna, <a href="/A359919/b359919.txt">Table of n, a(n) for n = 0..200</a>
%H A359919 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/QuintupleProductIdentity.html">Quintuple Product Identity</a>.
%F A359919 G.f. A(x) = Sum_{n>=1} a(n)*x^n satisfies the following.
%F A359919 (1) x^2 = Sum_{n=-oo..+oo} x^(n*(3*n+1)/2) * (A(x)^(3*n) - 1/A(x)^(3*n+1)).
%F A359919 (2) x^2 = Product_{n>=1} (1 - x^n) * (1 - x^n*A(x)) * (1 - x^(n-1)/A(x)) * (1 - x^(2*n-1)*A(x)^2) * (1 - x^(2*n-1)/A(x)^2), by the Watson quintuple product identity.
%e A359919 G.f.: A(x) = 1 + x^2 + 5*x^3 + 19*x^4 + 65*x^5 + 211*x^6 + 681*x^7 + 2255*x^8 + 7830*x^9 + 28786*x^10 + 111230*x^11 + 443789*x^12 + ...
%e A359919 where A = A(x) satisfies the doubly infinite sum
%e A359919 x^2 = ... + x^12*(1/A^9 - A^8) + x^5*(1/A^6 - A^5) + x*(1/A^3 - A^2) + (1 - 1/A) + x^2*(A^3 - 1/A^4) + x^7*(A^6 - 1/A^7) + x^15*(A^9 - 1/A^10) + ... + x^(n*(3*n+1)/2) * (A(x)^(3*n) - 1/A(x)^(3*n+1)) + ...
%e A359919 also, by the Watson quintuple product identity,
%e A359919 x^2 = (1-x)*(1-x*A)*(1-1/A)*(1-x*A^2)*(1-x/A^2) * (1-x^2)*(1-x^2*A)*(1-x/A)*(1-x^3*A^2)*(1-x^3/A^2) * (1-x^3)*(1-x^3*A)*(1-x^2/A)*(1-x^5*A^2)*(1-x^5/A^2) * (1-x^4)*(1-x^4*A)*(1-x^3/A)*(1-x^7*A^2)*(1-x^7/A^2) * ...
%o A359919 (PARI) /* Using the doubly infinite series */
%o A359919 {a(n) = my(A=[1,0]); for(i=1,n, A = concat(A,0);
%o A359919 A[#A] = polcoeff(x^2 - sum(m=-#A,#A, (Ser(A)^(3*m) - 1/Ser(A)^(3*m+1)) * x^(m*(3*m+1)/2) ),#A-1) ); A[n+1]}
%o A359919 for(n=0,30, print1(a(n),", "))
%o A359919 (PARI) /* Using the quintuple product */
%o A359919 {a(n) = my(A=[1,0]); for(i=1,n, A = concat(A,0);
%o A359919 A[#A] = polcoeff(x^2 - prod(m=1,#A, (1 - x^m) * (1 - x^m*Ser(A)) * (1 - x^(m-1)/Ser(A)) * (1 - x^(2*m-1)*Ser(A)^2) * (1 - x^(2*m-1)/Ser(A)^2) ),#A-1) ); A[n+1]}
%o A359919 for(n=0,30, print1(a(n),", "))
%Y A359919 Cf. A359920, A359921, A359924, A359915, A359916.
%Y A359919 Cf. A359914.
%K A359919 nonn
%O A359919 0,4
%A A359919 _Paul D. Hanna_, Jan 22 2023