A360240 Weakly decreasing triples of positive integers sorted lexicographically and concatenated.

1, 1, 1, 2, 1, 1, 2, 2, 1, 2, 2, 2, 3, 1, 1, 3, 2, 1, 3, 2, 2, 3, 3, 1, 3, 3, 2, 3, 3, 3, 4, 1, 1, 4, 2, 1, 4, 2, 2, 4, 3, 1, 4, 3, 2, 4, 3, 3, 4, 4, 1, 4, 4, 2, 4, 4, 3, 4, 4, 4, 5, 1, 1, 5, 2, 1, 5, 2, 2, 5, 3, 1, 5, 3, 2, 5, 3, 3, 5, 4, 1, 5, 4, 2, 5, 4, 3

Offset: 1

Author

Gus Wiseman, Feb 11 2023

Keywords

• nonn

Examples

			Triples begin: (1,1,1), (2,1,1), (2,2,1), (2,2,2), (3,1,1), (3,2,1), (3,2,2), (3,3,1), (3,3,2), (3,3,3), ...
		

Crossrefs

The triples have sums A070770.

Positions of first appearances are A158842.

For pairs instead of triples we have A330709 + 1.

The zero-based version is A331195.

- The first part is A360010 = A056556 + 1.

- The second part is A194848 = A056557 + 1.

- The third part is A333516 = A056558 + 1.

Cf. A002024, A003056, A069905.

Programs

Mathematica

nn=9;Join@@Select[Tuples[Range[nn],3],GreaterEqual@@#&]

Python

from math import isqrt, comb
from sympy import integer_nthroot
def A360240(n): return (m:=integer_nthroot((n-1<<1)+6,3)[0])+(n>3*comb(m+2,3)) if (a:=n%3)==1 else (k:=isqrt(r:=(b:=(n-1)//3)+1-comb((m:=integer_nthroot((n-1<<1)-1,3)[0])-(b(k<<2)*(k+1)+1) if a==2 else 1+(r:=(b:=(n-1)//3)-comb((m:=integer_nthroot((n-1<<1)-3,3)[0])+(b>=comb(m+2,3))+1,3))-comb((k:=isqrt(m:=r+1<<1))+(m>k*(k+1)),2) # Chai Wah Wu, Jun 07 2025

Formula

a(n) = A331195(n-1) + 1.