A360260 a(0) = 0, and for any n > 0, let k > 0 be as small as possible and such that T(3) + ... + T(2+k) >= n (where T(m) denotes A000073(m), the m-th tribonacci number); a(n) = k + a(T(3) + ... + T(2+k) - n).
0, 1, 3, 2, 5, 6, 4, 3, 8, 10, 9, 6, 7, 5, 4, 12, 11, 14, 15, 13, 8, 9, 11, 10, 7, 8, 6, 5, 16, 17, 15, 14, 19, 21, 20, 17, 18, 10, 11, 13, 12, 15, 16, 14, 9, 10, 12, 11, 8, 9, 7, 6, 21, 23, 22, 19, 20, 18, 17, 25, 24, 27, 28, 26, 21, 22, 24, 23, 12, 13, 15
Offset: 0
Examples
The first terms, alongside the corresponding k's, are: n a(n) k -- ---- --- 0 0 N/A 1 1 1 2 3 2 3 2 2 4 5 3 5 6 3 6 4 3 7 3 3 8 8 4 9 10 4 10 9 4 11 6 4 12 7 4 13 5 4 14 4 4 15 12 5
Links
- Rémy Sigrist, Table of n, a(n) for n = 0..10609
Programs
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PARI
tribonacci(n) = ([0,1,0; 0,0,1; 1,1,1]^n)[2,1] { t = k = 0; print1 (0); for (n = 1, #a = vector(70), if (n > t, t += tribonacci(2+k++);); print1 (", "a[n] = k+if (t==n, 0, a[t-n]));); }
Formula
a(A027084(n)) = n - 1.
Comments