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A362421 Number of nonisomorphic vector spaces consisting of n elements.

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%I A362421 #11 May 13 2023 06:18:55
%S A362421 1,1,2,1,0,1,2,2,0,1,0,1,0,0,3,1,0,1,0,0,0,1,0,2,0,2,0,1,0,1,2,0,0,0,
%T A362421 0,1,0,0,0,1,0,1,0,0,0,1,0,2,0,0,0,1,0,0,0,0,0,1,0,1,0,0,4,0,0,1,0,0,
%U A362421 0,1,0,1,0,0,0,0,0,1,0,3,0,1,0,0,0,0,0
%N A362421 Number of nonisomorphic vector spaces consisting of n elements.
%C A362421 If n is a prime power p^k, then a vector space consisting of n elements has the form (F_(p^d))^(k/d) where d is a divisor of k.
%H A362421 Philip Turecek, <a href="/A362421/b362421.txt">Table of n, a(n) for n = 2..1000</a>
%F A362421 a(n) = a(p^k) = sigma_0(k) if n = p^k is a prime power, a(n) = 0 otherwise.
%e A362421 a(16) = 3 because 16=2^4 and 4 has 3 divisors.
%o A362421 (Sage)
%o A362421 def f(a):
%o A362421     if not a.is_prime_power(): return 0
%o A362421     else: return sigma(factor(a)[0][1],0)
%K A362421 nonn
%O A362421 2,3
%A A362421 _Philip Turecek_, Apr 19 2023