cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A362855 a(n) = n for n <= 3; for n > 3, a(n) is the least novel multiple of k, the product of all distinct prime factors of a(n-2) that do not divide a(n-1).

Original entry on oeis.org

1, 2, 3, 4, 6, 5, 12, 10, 9, 20, 15, 8, 30, 7, 60, 14, 45, 28, 75, 42, 25, 84, 35, 18, 70, 21, 40, 63, 50, 105, 16, 210, 11, 420, 22, 315, 44, 525, 66, 140, 33, 280, 99, 350, 132, 175, 198, 245, 264, 385, 24, 770, 27, 1540, 36, 1155, 26, 2310, 13, 4620, 39, 3080, 78, 1925, 156, 2695, 234, 3465, 52, 5775
Offset: 1

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Keywords

Comments

Motivated by A362631, but instead of using one prime divisor of a(n-2) which does not divide a(n-1), the product of all such primes is used to compute a(n). - David James Sycamore, May 07 2023
From Michael De Vlieger, May 27 2023: (Start)
Primes p(k) enter the sequence in order and fairly regularly through a(20543) = p(15) = 47, immediately following primorial A002110(k-1). However, a(87723) = p(17) = 59 is the next prime to appear, following a(87722) = A002110(16).
Conjecture: all primes appear eventually, but not in order. (End)
Similar to A280866, except that the denominator here is rad(a(n-1)) instead of rad(a(n-2)). Also related to A369825. - David James Sycamore, Jan 27 2024
From Michael De Vlieger, Apr 23 2024: (Start)
Conjecture: permutation of natural numbers.
Conjecture: the smallest missing number is always either prime or a powerful number.
Primes do not appear in order; a(87723) = 59 but a(91307) = 53.
Powerful numbers appear in clusters, e.g., for n roughly between 91200 and 91320.
Though it appears primorials are always followed by primes, it is logically possible but rare that primorials can be followed by a composite number. (End)

Examples

			From _Michael De Vlieger_, Apr 23 2024: (Start)
Let rad(x) = A007947(x) and let P(x) = A002110(x).
Let S = { prime p : p | a(n-2) } and let T = { prime p : p | a(n-1) }. Then k = Product_{p in S\T} p = rad(a(n-2)*a(n-1))/rad(a(n-1)).
a(3) = 3 since rad(1*2)/rad(2) = 1; a(1) = 1, a(2) = 2, therefore a(3) = 3*1.
a(4) = 4 since rad(2*3)/rad(3) = 2; a(2) = 2, thus a(4) = 2*2.
a(5) = 6 since rad(3*4)/rad(4) = 6/2 = 3; a(3) = 3, thus a(5) = 2*3.
a(91305) = 108 and a(91306) = P(17), therefore k = 1 since rad(108) | P(17). The smallest missing number is 53, therefore a(91307) = 53*1. Related sequence A368133 = b is such that it is coincident with this sequence until b(91307) = 61, since prime(18) = 61 is the smallest prime that does not divide b(91306) = P(17). (End)
		

Crossrefs

Programs

  • Mathematica
    nn = 100; c[] := False; m[] := 1;
    f[x_] := f[x] = Times @@ FactorInteger[x][[All, 1]];
    Array[Set[{a[#], c[#], m[#]}, {#, True, 2}] &, 2]; i = 1; j = r = 2;
    Do[(While[c[Set[k, # m[#]]], m[#]++]) &[r/f[j]];
      Set[{a[n], c[k], i, j, r}, {k, True, j, k, f[j*k]}], {n, 3, nn}];
    Array[a, nn] (* Michael De Vlieger, Feb 21 2024 *)

Formula

A007947(a(n) * a(n+1)) | A007947(a(n+1) * a(n+2)). - Peter Munn, Apr 18 2024
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