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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A363573 Expansion of g.f. A(x) satisfying A(x) = 1 + x*(A(x) - A(x)^3 + A(x)^5).

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%I A363573 #9 Aug 15 2023 18:52:31
%S A363573 1,1,3,16,99,670,4804,35855,275635,2167577,17354844,140994899,
%T A363573 1159398760,9631155422,80703507043,681333999628,5789823864323,
%U A363573 49484286592503,425092050147999,3668385302806058,31786451503719132,276447315011186576,2412336247105063011,21114946136742383146
%N A363573 Expansion of g.f. A(x) satisfying A(x) = 1 + x*(A(x) - A(x)^3 + A(x)^5).
%F A363573 G.f. A(x) = Sum_{n>=0} a(n)*x^n may be defined by the following formulas.
%F A363573 (1) A(x) = 1 + x*(A(x) - A(x)^3 + A(x)^5).
%F A363573 (2) A(x)^2 = 1 + x*(A(x) + A(x)^2 - A(x)^3 - A(x)^4 + A(x)^5 + A(x)^6).
%F A363573 (3) A(x)^3 = 1 + x*(A(x) + A(x)^2 - A(x)^4 + A(x)^6 + A(x)^7).
%F A363573 (4) A(x)^4 = 1 + x*(A(x) + A(x)^2 + A(x)^7 + A(x)^8).
%F A363573 (5) A(x)^5 = 1 + x*(A(x) + A(x)^2 + A(x)^5 + A(x)^8 + A(x)^9).
%F A363573 (6) A(x)^6 = 1 + x*(A(x) + A(x)^2 + A(x)^5 + A(x)^6 + A(x)^9 + A(x)^10).
%F A363573 (7) A(x)^7 = 1 + x*(A(x) + A(x)^2 + A(x)^5 + A(x)^6 + A(x)^7 + A(x)^10 + A(x)^11).
%F A363573 (8) A(x) = (1/x) * Series_Reversion( x/(1 + Series_Reversion( x/(1 + x*(1+x)^2 + x*(1+x)^3) ) ) ).
%F A363573 (9) A(x) = 1 / A(-x*A(x)^5).
%e A363573 G.f.: A(x) = 1 + x + 3*x^2 + 16*x^3 + 99*x^4 + 670*x^5 + 4804*x^6 + 35855*x^7 + 275635*x^8 + 2167577*x^9 + 17354844*x^10 + ...
%e A363573 such that
%e A363573 A(x) = 1 + x*(A(x) - A(x)^3 + A(x)^5).
%e A363573 RELATED TABLE.
%e A363573 The table of coefficients in A(x)^n begins:
%e A363573 n=1: [1, 1,  3,  16,   99,   670,   4804,   35855,   275635, ...];
%e A363573 n=2: [1, 2,  7,  38,  239,  1634,  11798,   88506,   683045, ...];
%e A363573 n=3: [1, 3, 12,  67,  429,  2967,  21594,  162945,  1263183, ...];
%e A363573 n=4: [1, 4, 18, 104,  679,  4756,  34922,  265244,  2066591, ...];
%e A363573 n=5: [1, 5, 25, 150, 1000,  7101,  52645,  402725,  3155125, ...];
%e A363573 n=6: [1, 6, 33, 206, 1404, 10116,  75775,  584148,  4603911, ...];
%e A363573 n=7: [1, 7, 42, 273, 1904, 13930, 105490,  819918,  6503553, ...];
%e A363573 n=8: [1, 8, 52, 352, 2514, 18688, 143152, 1122312,  8962615, ...];
%e A363573 n=9: [1, 9, 63, 444, 3249, 24552, 190326, 1505727, 12110400, ...];
%e A363573 ...
%e A363573 from which one can verify the formulas involving powers of A(x).
%e A363573 RELATED SERIES.
%e A363573 Let G(x) = 1 + Series_Reversion( x/(1 + x*(1+x)^2 + x*(1+x)^3) )
%e A363573 where
%e A363573 G(x) = 1 + x + 2*x^2 + 9*x^3 + 42*x^4 + 219*x^5 + 1202*x^6 + 6867*x^7 + 40378*x^8 + 242782*x^9 + 1485836*x^10 + ...
%e A363573 then
%e A363573 A(x) = G(x*A(x)),
%e A363573 and so
%e A363573 A(x) = (1/x) * Series_Reversion( x/G(x) );
%e A363573 thus,
%e A363573 x*A(x) = (A(x) - 1) / (1 + (A(x) - 1)*(A(x)^2 + A(x)^3) )
%e A363573 which is equivalent to
%e A363573 A(x) = 1 + x*(A(x) - A(x)^3 + A(x)^5).
%p A363573 a:= n-> coeff(series(RootOf(1-A+x*(A-A^3+A^5), A), x, n+1), x, n):
%p A363573 seq(a(n), n=0..23);  # _Alois P. Heinz_, Aug 14 2023
%o A363573 (PARI) {a(n) = my(A=1+x); for(i=1, n, A = 1 + x*(A - A^3 + A^5) +x*O(x^n) ); polcoeff(A, n)}
%o A363573 for(n=0, 30, print1(a(n), ", "))
%Y A363573 Cf. A219537, A271469, A300048, A161634, A363560.
%K A363573 nonn
%O A363573 0,3
%A A363573 _Paul D. Hanna_, Aug 14 2023