A363653 a(1) = 1; for n > 1, a(n) = a(n-1) - A000005(n) if a(n) strictly positive, else a(n) = a(n-1) + A000005(n).
1, 3, 1, 4, 2, 6, 4, 8, 5, 1, 3, 9, 7, 3, 7, 2, 4, 10, 8, 2, 6, 2, 4, 12, 9, 5, 1, 7, 5, 13, 11, 5, 1, 5, 1, 10, 8, 4, 8, 16, 14, 6, 4, 10, 4, 8, 6, 16, 13, 7, 3, 9, 7, 15, 11, 3, 7, 3, 1, 13, 11, 7, 1, 8, 4, 12, 10, 4, 8, 16, 14, 2, 4, 8, 2, 8, 4, 12, 10, 20, 15, 11, 9, 21
Offset: 1
Keywords
Examples
a(1) = 1 a(2) = 1 + A000005(2) = 3
Programs
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Mathematica
a[1] = 1; a[n_] := a[n] = Module[{d = DivisorSigma[0, n]}, If[a[n - 1] > d, a[n - 1] - d, a[n - 1] + d]]; Array[a, 100] (* Amiram Eldar, Jun 13 2023 *)
Comments