A363654 Lexicographically earliest sequence of positive integers such that the n-th pair of identical terms encloses exactly a(n) terms.
1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, 11, 10, 12, 3, 9, 13, 7, 3, 11, 9, 14, 15, 13, 16, 17, 7, 18, 3, 19, 20, 11, 14, 9, 20, 17, 15, 19, 20, 18, 21, 11, 22, 3, 23, 24, 25, 26, 14, 17, 9, 27, 28, 29, 15, 26, 19
Offset: 1
Keywords
Examples
a(1) = 1. The 1st constructed pair encloses 1 term: [1, 2, 1]. a(2) = 2. The 2nd constructed pair encloses 2 terms: [2, 1, 3, 2]. a(3) = 1. The 3rd constructed pair encloses 1 term: [3, 2, 3]. a(4) = 3. The 4th constructed pair encloses 3 terms: [1, 3, 2, 3, 1]. a(5) = 2. The 5th constructed pair encloses 2 terms: [2, 3, 1, 2]. a(6) = 3. The 6th constructed pair encloses 3 terms: [3, 1, 2, 4, 3]. a(7) = 1. The 7th constructed pair encloses 1 term: [4, 3, 4]. ...
Links
- Neal Gersh Tolunsky, Table of n, a(n) for n = 1..10000
- Eric Angelini, A seq with a strange behavior (or not)?
- Neal Gersh Tolunsky, Scatterplot of first 100000 terms
Programs
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Python
from itertools import count, islice def agen(): # generator of terms a, indexes = [1], {1: 0} yield a[-1] for i in count(0): num = 1 while True: if num in indexes: if (len(a) - indexes[num]) == (a[i]+1): an = num; indexes[an] = len(a); a.append(an); yield an break else: num += 1 else: an = max(a)+1; indexes[an] = len(a); a.append(an); yield an num = 1 print(list(islice(agen(), 100))) # Gavin Lupo and Michael S. Branicky, Jun 13 2023
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