cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A365641 The minimum number of ways to label each triangle of a triangulation of an n-gon with one of its vertices so that different triangles get different labels (minimum taken over all triangulations).

Original entry on oeis.org

1, 3, 7, 14, 25, 41, 63, 92, 128, 173, 228, 293, 369, 458, 561, 676, 807, 955, 1119, 1300
Offset: 2

Views

Author

Günter Rote, Sep 14 2023

Keywords

Comments

Originally proposed by Johan Wästlund, Aug 28 2007, as an equivalent formulation of A089187.
The "fan triangulations", where one vertex is connected to all other vertices, is optimal up to a(9). Starting from a(10)=128, other triangulations are better.

Examples

			a(4)=7. Suppose a 4-gon ABCD is triangulated with triangles ABC and ACD. If ABC is labeled B, then ACD can be given 3 possible labels, while if ABC is labeled A or C, only 2 labels are available for ACD and 3+2+2=7. - Johan Wästlund, Aug 28 2007
		

Programs

  • Python
    """For a chosen "base edge" of a triangulated (n+2)-gon, (ul, ur, u2)
    denotes the numbers of labelings where the left, the right, or
    both vertices of the base edge have been used as labels.
    The number of labelings where none of the basepoints is used is always 1.
    tri[n] will contain the possible triplets (ul,ur,u2) for the
    triangulations of an (n+2)-gon."""
    tri = [{(0,0,0)}] # start with single edge (2-gon); no labels
    def combine(u,v):
        (ul,ur,u2),(vl,vr,v2) = u,v # formula obtained by combining the cases
        return (1+vl+ur+ul, 1+vl+ur+vr, vr+ul+(ul+ur)*(vl+vr)+u2+v2 )
    for n in range(1,18): # dynamic programming, requires large memory
        tri.append({combine(u,v) for k in range(n)
                    for u in tri[k] for v in tri[n-k-1]})
    print(", ".join(str(1+min(sum(t) for t in tr)) for tr in tri))