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A365675 a(n) = Sum_{k=0..n} p(k) where the p(k) are the partial sums of row n of A365676.

%I A365675 #8 Sep 17 2023 02:02:48
%S A365675 1,1,4,8,18,30,58,90,153,233,365,533,806,1142,1652,2308,3243,4431,
%T A365675 6103,8203,11080,14710,19540,25612,33612,43570,56476,72548,93080,
%U A365675 118490,150699,190315,240046,301042,376887,469515,583993,723073,893815,1100615,1352888
%N A365675 a(n) = Sum_{k=0..n} p(k) where the p(k) are the partial sums of row n of A365676.
%C A365675 If one reverses row n in the definition formula before accumulating, one gets A000070.
%o A365675 (Python)  # Using function A365676Row from A365676.
%o A365675 from itertools import accumulate
%o A365675 def A365675List(size: int) -> list[int]:
%o A365675     return [sum(accumulate(A365676Row(n))) for n in range(size)]
%o A365675 print(A365675List(41))
%Y A365675 Cf. A365676, A000070.
%K A365675 nonn
%O A365675 0,3
%A A365675 _Peter Luschny_, Sep 16 2023