A366492 Analog of A121805, but starting with 4.

4, 48, 129, 221, 233, 265, 318, 402, 426, 490, 494, 539, 635, 691, 708, 795, 853, 891, 910, 919, 1010, 1011, 1022, 1043, 1074, 1115, 1166, 1227, 1298, 1379, 1470, 1471, 1482, 1503, 1534, 1575, 1626, 1687, 1758, 1839, 1930, 1931, 1942, 1963, 1994, 2036, 2098, 2180, 2182

Offset: 1

Author

N. J. A. Sloane, Nov 14 2023

Keywords

• nonn
• base
• fini

Comments

If instead we start with 3, the sequence is the two-term sequence [3, 36].

The present sequence is finite, with last term a(199900) = 9999945.

Links

• N. J. A. Sloane, Table of n, a(n) for n = 1..20000

Crossrefs

Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.

Cf. A330128, A330129.

Programs

Python

from itertools import islice
def agen(start=4): # generator of terms
    an, y = start, 1
    while y < 10:
        yield an
        an, y = an + 10*(an%10), 1
        while y < 10:
            if str(an+y)[0] == str(y):
                an += y
                break
            y += 1
print(list(islice(agen(), 50))) # Michael S. Branicky, Nov 18 2023