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A367353 Analog of A121805, but starting with 9.

%I A367353 #12 Nov 18 2023 11:53:08
%S A367353 9,100,101,112,133,164,206,268,351,364,408,492,517,592,618,705,762,
%T A367353 789,887,966,1027,1098,1179,1270,1271,1282,1303,1334,1375,1426,1487,
%U A367353 1558,1639,1730,1731,1742,1763,1794,1835,1886,1947,2019,2111,2123,2155,2207,2279,2371
%N A367353 Analog of A121805, but starting with 9.
%C A367353 Contains 19511030 terms, the last being 999999936.
%H A367353 Michael De Vlieger, <a href="/A367353/b367353.txt">Table of n, a(n) for n = 1..10000</a>
%t A367353 b = 10; m = b - 1; a[1] = 9; a[n_] := a[n] = For[r = Mod[a[n - 1], b]; y = 0, y <= m, y++, If[y == IntegerDigits[#, b][[1]], Return[#]] &[a[n - 1] + b r + y]]; Array[a, 45] (* _Michael De Vlieger_, Nov 18 2023, after _Jean-François Alcover_ at A121805 *)
%o A367353 (Python)
%o A367353 from itertools import islice
%o A367353 def agen(start=9): # generator of terms
%o A367353     an, y = start, 1
%o A367353     while y < 10:
%o A367353         yield an
%o A367353         an, y = an + 10*(an%10), 1
%o A367353         while y < 10:
%o A367353             if str(an+y)[0] == str(y):
%o A367353                 an += y
%o A367353                 break
%o A367353             y += 1
%o A367353 print(list(islice(agen(), 50))) # _Michael S. Branicky_, Nov 18 2023
%Y A367353 Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.
%Y A367353 Cf. A330128, A330129.
%K A367353 nonn,base,fini
%O A367353 1,1
%A A367353 _N. J. A. Sloane_, Nov 17 2023