A368158 Irregular triangular array T, read by rows: T(n,k) = number of sums |x-y| + |y-z| = k, where x,y,z are in {1,2,...,n} and x <= y.
2, 3, 1, 3, 6, 6, 2, 1, 4, 9, 11, 9, 4, 2, 1, 5, 12, 16, 16, 13, 6, 4, 2, 1, 6, 15, 21, 23, 22, 17, 9, 6, 4, 2, 1, 7, 18, 26, 30, 31, 28, 22, 12, 9, 6, 4, 2, 1, 8, 21, 31, 37, 40, 39, 35, 27, 16, 12, 9, 6, 4, 2, 1, 9, 24, 36, 44, 49, 50, 48, 42, 33, 20, 16
Offset: 1
Examples
First six rows: 2 3 1 3 6 6 2 1 4 9 11 9 4 2 1 5 12 16 16 13 6 4 2 1 6 15 21 23 22 17 9 6 4 2 1 7 18 26 30 31 28 22 12 9 6 4 2 1 For n=2, there are 6 triples (x,y,z) having x <= y: 111: |x-y| + |y-z| = 0 112: |x-y| + |y-z| = 1 121: |x-y| + |y-z| = 2 122: |x-y| + |y-z| = 1 221: |x-y| + |y-z| = 1 222: |x-y| + |y-z| = 0, so row 1 of the array is (2,3,1), representing two 0s, three 1s, and one 1.
Crossrefs
Programs
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Mathematica
t1[n_] := t1[n] = Tuples[Range[n], 3]; t[n_] := t[n] = Select[t1[n], #[[1]] < #[[2]] &]; a[n_, k_] := Select[t[n], Abs[#[[1]] - #[[2]]] + Abs[#[[2]] - #[[3]]] == k &]; u = Table[Length[a[n, k]], {n, 2, 15}, {k, 0, 2 n - 2}]; v = Flatten[u] (* sequence *) Column[Table[Length[a[n, k]], {n, 2, 15}, {k, 0, 2 n - 2}]] (* array *)
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