A368515 Irregular triangular array T, read by rows: T(n,k) = number of sums |x-y|+|y-z| = k, where x,y,z are in {1,2,...,n} and x != y.
2, 2, 4, 8, 4, 2, 6, 14, 14, 8, 4, 2, 8, 20, 24, 22, 12, 8, 4, 2, 10, 26, 34, 36, 30, 18, 12, 8, 4, 2, 12, 32, 44, 50, 48, 40, 24, 18, 12, 8, 4, 2, 14, 38, 54, 64, 66, 62, 50, 32, 24, 18, 12, 8, 4, 2, 16, 44, 64, 78, 84, 84, 76, 62, 40, 32, 24, 18, 12, 8, 4
Offset: 1
Examples
First six rows: 2 2 4 8 4 2 6 14 14 8 4 2 8 20 24 22 12 8 4 2 10 26 34 36 30 18 12 8 4 2 12 32 44 50 48 40 24 18 12 8 4 2 For n=2, there are 4 triples (x,y,z) having x != y: 121: |x-y| + |y-z| = 2 122: |x-y| + |y-z| = 1 211: |x-y| + |y-z| = 1 212: |x-y| + |y-z| = 2, so that row 2 of the array is (2,2), representing two 1s and two 2s.
Crossrefs
Programs
-
Mathematica
t1[n_] := t1[n] = Tuples[Range[n], 3]; t[n_] := t[n] = Select[t1[n], #[[1]] != #[[2]] &]; a[n_, k_] := Select[t[n], Abs[#[[1]] - #[[2]]] + Abs[#[[2]] - #[[3]]] == k &]; u = Table[Length[a[n, k]], {n, 2, 15}, {k, 1, 2 n - 2}]; v = Flatten[u]; (* sequence *) Column[Table[Length[a[n, k]], {n, 2, 15}, {k, 1, 2 n - 2}]] (* array *)
Comments