A368606 Irregular triangular array T, read by rows: T(n,k) = number of sums |x-y| + |y-z| = k, where x,y,z are in {1,2,...,n} and x <= y and y >= z.
1, 2, 2, 1, 3, 4, 4, 2, 1, 4, 6, 7, 6, 4, 2, 1, 5, 8, 10, 10, 9, 6, 4, 2, 1, 6, 10, 13, 14, 14, 12, 9, 6, 4, 2, 1, 7, 12, 16, 18, 19, 18, 16, 12, 9, 6, 4, 2, 1, 8, 14, 19, 22, 24, 24, 23, 20, 16, 12, 9, 6, 4, 2, 1, 9, 16, 22, 26, 29, 30, 30, 28, 25, 20, 16
Offset: 1
Examples
First six rows: 1 2 2 1 3 4 4 2 1 4 6 7 6 4 2 1 5 8 10 10 9 6 4 2 1 6 10 13 14 14 12 9 6 4 2 1 For n=2, there are 5 triples (x,y,z) having x <= y and y >= z: 111: |x-y| + |y-z| = 0 121: |x-y| + |y-z| = 2 122: |x-y| + |y-z| = 1 221: |x-y| + |y-z| = 1 222: |x-y| + |y-z| = 0 so row 2 of the array is (2,2,1), representing two 0s, two 1s, and one 3.
Crossrefs
Programs
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Mathematica
t1[n_] := t1[n] = Tuples[Range[n], 3]; t[n_] := t[n] = Select[t1[n], #[[1]] <= #[[2]] >= #[[3]] &]; a[n_, k_] := Select[t[n], Abs[#[[1]] - #[[2]]] + Abs[#[[2]] - #[[3]]] == k &]; u = Table[Length[a[n, k]], {n, 1, 15}, {k, 0, 2 n - 2}]; v = Flatten[u] (* sequence *) Column[Table[Length[a[n, k]], {n, 1, 15}, {k, 0, 2 n - 2}]] (* array *)
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