A368607 Irregular triangular array T, read by rows: T(n,k) = number of sums |x-y| + |y-z| = k, where x,y,z are in {1,2,...,n} and x != y and y < z.
1, 3, 2, 1, 5, 6, 4, 2, 1, 7, 10, 10, 6, 4, 2, 1, 9, 14, 16, 14, 9, 6, 4, 2, 1, 11, 18, 22, 22, 19, 12, 9, 6, 4, 2, 1, 13, 22, 28, 30, 29, 24, 16, 12, 9, 6, 4, 2, 1, 15, 26, 34, 38, 39, 36, 30, 20, 16, 12, 9, 6, 4, 2, 1, 17, 30, 40, 46, 49, 48, 44, 36, 25
Offset: 1
Examples
First six rows: 1 3 2 1 5 6 4 2 1 7 10 10 6 4 2 1 9 14 16 14 9 6 4 2 1 11 18 22 22 19 12 9 6 4 2 1 For n=3, there are 6 triples (x,y,z) having x != y and y < z: 123: |x-y| + |y-z| = 2 212: |x-y| + |y-z| = 2 213: |x-y| + |y-z| = 3 312: |x-y| + |y-z| = 3 313: |x-y| + |y-z| = 4 323: |x-y| + |y-z| = 2 so row 2 of the array is (3,2,1), representing three 2s, two 3s, and one 4.
Crossrefs
Programs
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Mathematica
t1[n_] := t1[n] = Tuples[Range[n], 3]; t[n_] := t[n] = Select[t1[n], #[[1]] != #[[2]] < #[[3]] &]; a[n_, k_] := Select[t[n], Abs[#[[1]] - #[[2]]] + Abs[#[[2]] - #[[3]]] == k &]; u = Table[Length[a[n, k]], {n, 2, 15}, {k, 2, 2 n - 2}]; v = Flatten[u] (* sequence *) Column[Table[Length[a[n, k]], {n, 2, 15}, {k, 2, 2 n - 2}]] (* array *)
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