A370708 a(1)=1; thereafter a(n) is the smallest number > a(n-1) such that no two triples of earlier terms in arithmetic progression have the same common difference.
1, 2, 3, 5, 6, 8, 12, 13, 15, 16, 21, 23, 28, 32, 37, 38, 40, 45, 47, 61, 63, 70, 73, 80, 81, 91, 96, 100, 103, 105, 116, 123, 128, 134, 138, 150, 156, 157, 175, 179, 181, 190, 207, 210, 214, 217, 226, 240, 243, 252, 256, 265, 275, 281, 283, 289, 292, 293, 308, 315
Offset: 1
Keywords
Examples
4 is not a term in the sequence because it would create the arithmetic progression (2,3,4), which has the same common difference (1) as the previously occurring triple (1,2,3). 9 is not a term because it would create the arithmetic progression (3,6,9), which has the same common difference (3) as the previously occurring (2,5,8).
Links
- Michael S. Branicky, Table of n, a(n) for n = 1..10000
Crossrefs
Cf. A003278.
Programs
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Python
from itertools import islice def cd(k, alst, dset, diff_dict): newdset = set() for a in alst: if k-a in diff_dict[a]: if k-a in dset: return False else: newdset.add(k-a) return True, newdset def agen(): # generator of terms alst, dset, an = [1, 2, 3], {1}, 3 yield from alst diff_dict = {1: set(), 2: {1}, 3: {1, 2}} while True: k = an+1 while not (ans:=cd(k, alst, dset, diff_dict)): k += 1 dset.update(ans[1]) an = k diff_dict[k] = {an-a for a in alst} alst.append(an) yield an print(list(islice(agen(), 60))) # Michael S. Branicky, Mar 30 2024
Extensions
a(15) and beyond from Michael S. Branicky, Mar 30 2024
Comments