A371263 The run lengths transform of the balanced ternary expansion of n corresponds to the run lengths transform of the binary expansion of a(n).
0, 1, 2, 2, 3, 4, 5, 5, 5, 4, 5, 6, 6, 7, 8, 9, 9, 10, 11, 10, 10, 10, 11, 11, 10, 10, 9, 8, 9, 10, 10, 11, 12, 13, 13, 13, 12, 13, 14, 14, 15, 16, 17, 17, 18, 19, 18, 18, 18, 19, 20, 21, 21, 22, 23, 22, 21, 21, 20, 20, 21, 21, 21, 20, 21, 22, 22, 23, 23, 22
Offset: 0
Examples
The first terms, alongside the balanced ternary expansion of n and the binary expansion of a(n), are: n a(n) bter(n) bin(a(n)) -- ---- ------- --------- 0 0 0 0 1 1 1 1 2 2 1T 10 3 2 10 10 4 3 11 11 5 4 1TT 100 6 5 1T0 101 7 5 1T1 101 8 5 10T 101 9 4 100 100 10 5 101 101 11 6 11T 110 12 6 110 110 13 7 111 111 14 8 1TTT 1000 15 9 1TT0 1001
Links
- Rémy Sigrist, Table of n, a(n) for n = 0..9841
Programs
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PARI
a(n) = { my (r = [], d, l, v = 0); while (n, d = centerlift(Mod(n, 3)); l = 0; while (centerlift(Mod(n, 3))==d, n = (n-d)/3; l++;); r = concat(l, r);); for (k = 1, #r, v = (v+k%2)*2^r[k]-k%2); v }
Formula
abs(a(n+1) - a(n)) <= 1.
Comments