A372011 Orders of finite groups for which there is at least one group G such that |Aut(G)| = |G|.
1, 6, 8, 12, 16, 20, 24, 32, 36, 40, 42, 48, 54, 64, 72, 80, 84, 96, 108, 110, 120, 126, 128, 144, 156, 160, 162, 168, 192, 216, 220, 240, 252, 256, 272, 288, 312, 320, 324, 336, 342, 378, 384, 432, 440, 468, 480, 486, 500, 504, 506, 512, 544, 550, 576, 624, 640, 648, 660, 672
Offset: 1
Keywords
Examples
a(2) = 6 since the symmetric group of order 6 has 6 automorphisms.
Crossrefs
Cf. A341298 (orders of complete groups).
Programs
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GAP
for n in [1..32] do for i in [1..NrSmallGroups(n)] do if Size(AutomorphismGroup(SmallGroup(n,i))) = n then Print(n,","," "); break; fi; od; od;
Formula
|Out(G)|<=|G| for every entry.
Comments