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A372313 Table read by antidiagonals: A(n,1) = 2n-1, and for k > 1, A(n,k) = A372289(A(n,k-1)+A(n,1)).

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%I A372313 #27 May 31 2024 13:55:08
%S A372313 1,5,3,13,13,5,29,341,21,7,61,2773,53,29,9,125,22229,117,149,37,11,
%T A372313 253,177877,245,629,93,45,13,509,1423061,501,2549,205,469,53,15,1021,
%U A372313 11384533,1013,10229,429,15701,133,61,17,2045,91076309,2037,40949,877,503125,293,309,69,19
%N A372313 Table read by antidiagonals: A(n,1) = 2n-1, and for k > 1, A(n,k) = A372289(A(n,k-1)+A(n,1)).
%C A372313 Conjecture: if A(n,1) is congruent to 33 (mod 100), then all terms on the n-th row are congruent to 33 (mod 100).
%e A372313 A(3,1) = 5. A(3,2) = A372289(5+5) = 21. A(3,3) = A372289(21+5) = 53. A(3,4) = A372289(53+5) = 117.
%e A372313 Table begins:
%e A372313   1,  5,   13,   29,     61,        125,          253,           509, ...
%e A372313   3,  13,  341,  2773,   22229,     177877,       1423061,       11384533, ...
%e A372313   5,  21,  53,   117,    245,       501,          1013,          2037, ...
%e A372313   7,  29,  149,  629,    2549,      10229,        40949,         163829, ...
%e A372313   9,  37,  93,   205,    429,       877,          1773,          3565, ...
%e A372313   11, 45,  469,  15701,  503125,    16100693,     515222869,     16487132501, ...
%e A372313   13, 53,  133,  293,    613,       1253,         2533,          5093, ...
%e A372313   15, 61,  309,  1301,   5269,      21141,        84629,         338581, ...
%e A372313   17, 69,  173,  381,    797,       1629,         3293,          6621, ...
%e A372313   19, 77,  3413, 27477,  219989,    1760085,      14080853,      112646997, ...
%Y A372313 Cf. A086893, A372289.
%K A372313 nonn,tabl
%O A372313 1,2
%A A372313 _Ali Sada_, Apr 26 2024