A373738 a(1) = 1, a(n) = floor((1/omega(n)!) * Product_{p | n} 1 + (log n)/(log p)), where omega = A001221.
1, 2, 2, 3, 2, 4, 2, 4, 3, 5, 2, 7, 2, 5, 4, 5, 2, 9, 2, 7, 4, 6, 2, 10, 3, 6, 4, 7, 2, 12, 2, 6, 5, 6, 4, 13, 2, 6, 5, 10, 2, 13, 2, 8, 7, 7, 2, 14, 3, 11, 5, 8, 2, 15, 4, 10, 5, 7, 2, 19, 2, 7, 7, 7, 4, 15, 2, 8, 5, 13, 2, 17, 2, 7, 9, 8, 4, 16, 2, 13, 5, 8, 2
Offset: 1
Keywords
Examples
Let b = A010846. a(6) = 4 since the floor of the area of a right triangle with axial edge lengths {1+log_p 6 : p | 6} = {3.58496..., 2.63093...}, a(6) = floor(9.43178.../2) = 4. b(6) = 5. a(10) = 5 since the floor of the area of a right triangle with axial edge lengths {1+log_p 12 : p | 12} = {4.32193..., 2.43068...}, a(10) = floor(10.5052.../2) = 5. b(10) = 6. a(30) = 12 since the floor of the volume of a trirectangular tetrahedron with axial edge lengths {1+log_p 30 : p | 30} = {5.90689..., 4.0959..., 3.11328...}, a(30) = floor(75.3229.../6) = 12. b(30) = 18. a(210) = 34 since the floor of the content of a 4-simplex with a vertex with orthogonal edges at origin and axial edge lengths {1+log_p 210 : p | 210} = {8.71425..., 5.86715..., 4.32234..., 3.74787...}, a(210) = floor(828.248.../24) = 12. b(210) = 68, etc.
Links
- Michael De Vlieger, Table of n, a(n) for n = 1..10000
- Michael De Vlieger, Comparison of S(900) in red with R(900) in blue
- Eric Weisstein's World of Mathematics, Simplex.
Programs
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Mathematica
{1}~Join~Table[Floor[(1/PrimeNu[n]!)*Times @@ Map[Log[#, n] + 1 &, FactorInteger[n][[All, 1]] ] ], {n, 2, 82}]
Comments