A373927 a(n) is the minimum number of hypercubes needed to admit a hole of size n in the 4D tesseractic honeycomb.

16, 80, 106, 132

Offset: 0

Author

Abraham Maxfield, Jun 22 2024

Keywords

• nonn
• more

Examples

			16 hypercubes surround a single vertex so a(0) = 16.
A 3 X 3 X 3 X 3 hypercube will admit a single hole in its center, so a(1) = 3*3*3*3 - 1 = 80.
		

Crossrefs

Cf. A345205 (3D equivalent), A235382 (2D equivalent).