A374987 Let s(x) be the Maclaurin series for cos(x); then a(n) is the least index k for which all partial sums of cos(2m*Pi) are positive.
6, 14, 24, 32, 40, 48, 58, 66, 74, 82, 92, 100, 108, 116, 126, 134, 142, 150, 160, 168, 176, 184, 194, 202, 210, 218, 228, 236, 244, 254, 262, 270, 278, 288, 296, 304, 312, 322, 330, 338, 346, 356, 364, 372, 382, 390, 398, 406, 416, 424, 432, 440, 450, 458
Offset: 0
Keywords
Examples
For n=1, the partial sums (for k = 0,1,2,3,4,5,6,7) are approximately 1, -18.7, 46.2, -39.2, 20.9, -5.4, 2.4, 0.7; beginning with k=6, the partials sums are all positive, so a(1)=6.
Programs
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Mathematica
z = 800; r = Pi; f[m_, n_] := f[m, n] = N[Sum[(-1)^k (2 m r)^(2 k)/(2 k)!, {k, 0, n}], 10] g[m_] := Select[Range[z], f[m, #] > 0 && f[m, # + 1] > 0 &, 1] Flatten[Table[g[m], {m, 1, 80}]]