A375246 Number of biquadratefree numbers <= 10^n.
1, 10, 93, 925, 9240, 92395, 923939, 9239385, 92393839, 923938406, 9239384029, 92393840300, 923938402926, 9239384029211, 92393840292169, 923938402921591, 9239384029215891, 92393840292159004, 923938402921590127, 9239384029215901651, 92393840292159016603
Offset: 0
Keywords
Links
- Chai Wah Wu, Table of n, a(n) for n = 0..39
Programs
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Python
from sympy import mobius, integer_nthroot def A375246(n): return int(sum(mobius(k)*(10**n//k**4) for k in range(1, integer_nthroot(10**n,4)[0]+1)))
Formula
a(n) = A375245(10^n).
Comments