A376181 Array read by antidiagonals: Start from 1 and thereafter add gnomons of terms for each t >= 2 with width a(t-1).
1, 2, 2, 3, 2, 3, 3, 3, 3, 3, 4, 3, 3, 3, 4, 4, 4, 3, 3, 4, 4, 5, 4, 4, 3, 4, 4, 5, 5, 5, 4, 4, 4, 4, 5, 5, 5, 5, 5, 4, 4, 4, 5, 5, 5, 6, 5, 5, 5, 4, 4, 5, 5, 5, 6, 6, 6, 5, 5, 5, 4, 5, 5, 5, 6, 6, 7, 6, 6, 5, 5, 5, 5, 5, 5, 6, 6, 7, 7, 7, 6, 6, 5, 5, 5, 5, 5, 6, 6, 7, 7, 7, 7, 7, 6, 6, 5, 5, 5, 5
Offset: 1
Examples
Array begins: k=1 2 3 4 5 6 n=1: 1 2 3 3 4 4 n=2: 2 2 3 3 4 4 n=3: 3 3 3 3 4 4 n=4: 3 3 3 3 4 4 n=5: 4 4 4 4 4 4 n=6: 4 4 4 4 4 4 The first three terms by antidiagonals are 1,2,2 and they are the widths of the gnomons comprising terms 2,3,4 respectively.
Formula
a(d(d+1)/2) = n, where d = 1 + (a(1) + ... + a(n-1)), for n > 1.
a(n) ~ k*n^c, on average, where c = (sqrt(3)-1)/2 = 0.366... (heuristic).
max{a(i); i < n} ~ K*n^e with e ~ 0.387... (empirical).
Comments