cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A377124 Phase shift (original name "sfasamento") of the tetration base 10*n at any height greater than or equal to 3.

Original entry on oeis.org

1, 6, 1, 6, 5, 6, 1, 6, 1, 1, 1, 6, 1, 6, 5, 6, 1, 6, 1, 6, 1, 6, 1, 6, 5, 6, 1, 6, 1, 1, 1, 6, 1, 6, 5, 6, 1, 6, 1, 6, 1, 6, 1, 6, 5, 6, 1, 6, 1, 5, 1, 6, 1, 6, 5, 6, 1, 6, 1, 6, 1, 6, 1, 6, 5, 6, 1, 6, 1, 1, 1, 6, 1, 6, 5, 6, 1, 6, 1, 6, 1, 6, 1, 6, 5, 6, 1
Offset: 1

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Author

Marco Ripà, Oct 17 2024

Keywords

Comments

Let m^^b be m^m^...^m b-times (integer tetration).
For any n, the phase shift of n*10 at height b is defined as the congruence class modulo 10 of the difference between the least significant non-stable digit of (n*10)^^b and the corresponding digit of (n*10)^^(b+1), so the phase shift of n*10 at height 1 is trivially A065881(n) while the phase shift of n*10 at height 2 is given by A376838(n).
Thus, assume b >= 3 and, for any given tetration base n*10, this sequence represents the congruence classes modulo 10 of the differences between the rightmost non-stable digit of (n*10)^^b and the zero of (n*10)^^(b+1) which occupies the same decimal position (counting from right to the left) as the rightmost nonzero digit of (n*10)^^b (see Appendix of "Graham's number stable digits: an exact solution" in Links).
If n == 3,7 (mod 10), a(n) <> A065881(n) since the least significant nonzero digit of (n*10)^^b only depends on the last digit of n^^(b - 1) and, in the mentioned two cases, n*10 is not congruent to 0 modulo 4, whereas (n*10)^(n*10) is clearly a multiple of 4 given the fact that it is also a multiple of 100 (e.g., if n = 3 is given, the last nonzero digit of (n*10)^(n*10) is 3 iff (n*10) == 1 (mod 4), 9 iff (n*10) == 2 (mod 4), 7 iff (n*10) == 3 (mod 4), 1 iff (n*10) == 0 (mod 4), which is the only case we are considering here since (3*10)^(3*10) == 0 (mod 100)).

Examples

			a(1) = 1 since 10^(10^10) == 0 (mod 10^10000000000) and 10^(10^10) == 1 (mod 10^10000000001), and trivially 1 - 0 = 1.
		

References

  • Marco Ripà, La strana coda della serie n^n^...^n, Trento, UNI Service, Nov 2011. ISBN 978-88-6178-789-6.

Crossrefs

Formula

a(n) equals the least significant nonzero digit of n^((n*10)^(n*10)).
Let h indicate the least significant nonzero digit of n. Then,
a(n) = 1 iff h = 1,3,7,9;
a(n) = 5 iff h = 5;
a(n) = 6 iff h = 2,4,6,8.