A377971 Square array of primes p >= 7, read by decreasing antidiagonals. Each row lists, in increasing order, the primes that share the same sum of their neighboring prime gaps.
7, 11, 29, 13, 31, 23, 17, 59, 37, 53, 19, 61, 47, 97, 89, 41, 73, 67, 139, 199, 223, 43, 137, 79, 149, 359, 251, 113, 71, 151, 83, 157, 367, 337, 127, 331, 101, 179, 131, 173, 389, 467, 307, 479, 631, 103, 239, 163, 181, 449, 547, 317, 523, 797, 211, 107, 269, 167, 191, 521, 557, 409, 953, 1087, 293, 1381
Offset: 1
Examples
Square array begins: . S = pg_inf + pg_sup | 2*(3..k) | ----------------------------------------------------------------------- 6 | 7, 11, 13, 17, 19, 41, 43, 71, 101, ... A098414 8 | 29, 31, 59, 61, 73, 137, 151, 179, 239, ... 10 | 23, 37, 47, 67, 79, 83, 131, 163, 167, ... 12 | 53, 97, 139, 149, 157, 173, 181, 191, 241, ... 14 | 89, 199, 359, 367, 389, 449, 521, 619, 661, ... . 31, 59 and 179 are in the same row because their preceding and succeeding prime gaps, (pg_inf, pg_sup), respectively (2,6), (6,2) and (6,2) each equally sum up to 8. 53 and 181 are in the same row because their preceding and succeeding prime gaps, (pg_inf, pg_sup), respectively (6,6) and (2,10) each equally sum up to 12. Here, 53 also happens to be a balanced prime as its corresponding gaps, (6,6), are equal.
Formula
Sum_prime_gaps_a(n) = S_a(n) = (A002260(n))*2 + 4.
Comments