cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A378789 Numbers k such that tau(k) == 1 (mod(2*(tau(k+prime(k)-1)))), where tau(k) = A000005(k).

Original entry on oeis.org

1, 81, 225, 256, 441, 625, 1521, 2601, 3025, 3249, 3364, 4761, 5929, 6561, 7225, 8281, 9025, 9216, 12321, 13225, 14161, 17689, 18225, 20449, 21025, 25921, 27556, 31684, 34225, 41209, 43681, 45369, 45796, 46225, 47089, 47961, 48841, 50176, 50625, 57600, 61009, 62001, 67081
Offset: 1

Views

Author

Claude H. R. Dequatre, Dec 07 2024

Keywords

Comments

98 terms < 5*10^5 were found.
All terms are squares because their number of divisors is odd (see formula field in A000005: a(n) is odd iff n is square).

Examples

			1 is a term because tau(1) = 1, tau(1 + 2 - 1) = 2 and 1 modulo 4 is 1.
81 is a term because tau(81) = 5, tau(81 + 419 - 1) = 2 and 5 modulo 4 is 1.
85 is not a term because tau(85) = 4, tau(85 + 439 - 1) = 2 and 4 modulo 4 = 0.
		

Crossrefs

Programs

  • PARI
    isok(k)=my(d_1=numdiv(k),d_2=numdiv(k+prime(k)-1));d_1%(2*d_2)==1;
    for(k=1,1000,if(isok(k),print1(k", ")))

A378794 Numbers k such that tau(k) == 1 (mod(2*(tau(k^2 + k - 1)))), where tau(k) = A000005(k).

Original entry on oeis.org

1, 16, 36, 100, 196, 225, 256, 441, 484, 625, 676, 1089, 1156, 1225, 1296, 2116, 2601, 3136, 3249, 3364, 3844, 4225, 5929, 6561, 7056, 7225, 7569, 8100, 8281, 8836, 9216, 10000, 11236, 12321, 13924, 14161, 14884, 15129, 16641, 17689, 17956, 19881, 20164, 20449
Offset: 1

Views

Author

Claude H. R. Dequatre, Dec 07 2024

Keywords

Comments

736 terms < 10^7 were found.
All terms are squares because their number of divisors is odd (see formula field in A000005: a(n) is odd iff n is square).

Examples

			1 is a term because tau(1) = 1, tau(1 + 1 - 1) = 1 and 1 modulo 2 is 1.
16 is a term because tau(16) = 5, tau(256 + 16 - 1) = 2 and 5 modulo 4 is 1.
50 is not a term because tau(50) = 6, tau(2500 + 50 -1) = 2 and 6 modulo 4 is 2.
		

Crossrefs

Programs

  • PARI
    isok(k)=my(d_1=numdiv(k),d_2=numdiv(k^2+k-1));d_1%(2*d_2)==1;
    for(k=1,1000,if(isok(k),print1(k", ")))
Showing 1-2 of 2 results.