cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A378847 Smallest starting x which takes n tripling steps to reach the minimum of a cycle in the 3x-1 iteration.

Original entry on oeis.org

1, 3, 15, 13, 9, 37, 25, 33, 45, 57, 145, 97, 65, 87, 159, 165, 225, 273, 391, 261, 647, 465, 741, 529, 353, 471, 921, 837, 865, 577, 385, 257, 343, 229, 153, 407, 543, 721, 481, 321, 855, 1141, 761, 1015, 677, 903, 1209, 1605, 2149, 1433, 1911, 2529, 3397, 2265
Offset: 0

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Author

Kevin Ryde, Dec 15 2024

Keywords

Comments

Each step is x -> 3x-1 if x odd, or x -> x/2 if x even (A001281) and here only the tripling steps 3x-1 are counted.
The number of tripling steps is A378833(x) so that a(n) = x is the smallest x for which A378833(x) = n.
All terms are odd since any even x takes a first step to x/2 which is a smaller start for the same number of tripling steps.
a(n) >= L(n) = (2*a(n-1) + 1)/3 is a lower bound since a(n) = x must at least have a first step 3x-1 and halve to (3x-1)/2, then n-1 further tripling steps, so (3x-1)/2 >= a(n-1).
Equality a(n) = L(n) occurs iff L(n) is an integer and not a cycle minimum.
A large upper bound for n>=1, showing a(n) always exists, is a(n) <= U(n) = (4^(3^n) - 1)*2^n/3^n + 1, since U(n) is a candidate for a(n) by taking n steps of (3x-1)/2 to reach 4^(3^n) which is a power of 2.
Tighter upper bounds on a(n) can be found by taking predecessor steps back from a(n-c) seeking c tripling steps to reach a(n-c) if that's possible (which for instance it's not if a(n-c) == 0 (mod 3)).
Such predecessors are candidates for a(n), but the actual a(n) might have a trajectory which does not go through any previous a(n-c).

Examples

			For n=4, a(4) = 9 has 4 tripling steps on its way to 5 which is the minimum of a cycle:
  9 -> 26 -> 13 -> 38 -> 19 -> 56 -> 28 -> 14 -> 7 -> 20 -> 10 -> 5
    ^            ^           ^                      ^
This a(4) = 9 is an example where a(n) is at its lower bound L(n), in this case a(3) = 13 has L(4) = (2*a(3)+1)/3 = 9 which is an integer and not a cycle minimum.
		

Crossrefs

Cf. A001281 (step), A378833 (number of triplings).
Cf. A378845 (with all steps), A378846 (with halving steps).

Programs

  • C
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