A379545 Triangle read by rows where row n lists powerful divisors d | n (i.e., d in A001694).
1, 1, 1, 1, 4, 1, 1, 1, 1, 4, 8, 1, 9, 1, 1, 1, 4, 1, 1, 1, 1, 4, 8, 16, 1, 1, 9, 1, 1, 4, 1, 1, 1, 1, 4, 8, 1, 25, 1, 1, 9, 27, 1, 4, 1, 1, 1, 1, 4, 8, 16, 32, 1, 1, 1, 1, 4, 9, 36, 1, 1, 1, 1, 4, 8, 1, 1, 1, 1, 4, 1, 9, 1, 1, 1, 4, 8, 16, 1, 49, 1, 25, 1, 1, 4
Offset: 1
Examples
D(1) = {1} = row 1 of this sequence since 1 | 1 is powerful. D(2) = {1, 2}; of these, only 1 is powerful. D(4) = {1, 2, 4}; of these, only 2 is not powerful, so row 4 = {1, 4}. D(6) = {1, 2, 3, 6}; of these, only 1 is powerful. D(8) = {1, 2, 4, 8}; of these, only 2 is not powerful, so row 4 = {1, 4, 8}. D(12) = {1, 2, 3, 4, 6, 12}; of these, only {1, 4} are powerful. D(36) = {1, 2, 3, 4, 6, 9, 12, 18, 36}; of these, only {1, 4, 9, 36} are powerful, etc. Table begins: n: row n ---------------- 1: 1; 2: 1; 3: 1; 4: 1, 4; 5: 1; 6: 1; 7: 1; 8: 1, 4, 8; 9: 1, 9; 10: 1; 11: 1; 12: 1, 4; 13: 1; 14: 1; 15: 1; 16: 1, 4, 8, 16; ...
Links
- Michael De Vlieger, Table of n, a(n) for n = 1..11445 (rows n = 1..6000, flattened).
Programs
-
Mathematica
rad[x_] := rad[x] = Times @@ FactorInteger[x][[All, 1]]; Table[Select[Divisors[n], Divisible[#, rad[#]^2] &], {n, 2, 60}] // Flatten
-
PARI
row(n) = select(x -> ispowerful(x), divisors(n)); \\ Amiram Eldar, May 02 2025
Formula
First term in row n is 1.
Row n does not contain squarefree factors of n, and also does not contain factors in A332785.
For squarefree n, row n = {1}.
Let D(n) = row n of A027750. For prime p and m > 0, row p^m = D(p^m) \ {p}, since d = 1 and p = p^j, j > 1 are powerful, but primes are squarefree (and not powerful).
Comments