A381585 Starts of runs of 5 consecutive integers that are all terms in A381581.

57744971, 159104411, 203738652, 212548572, 260463851, 361823291, 413644572, 431577521, 440353328, 520800012, 717222337, 726300972, 779825648, 843559091, 913313321, 945016812, 986681527, 1091786528, 1116032201, 1185786431, 1318751081, 1347208812, 1360423692, 1418212627

Offset: 1

Author

Amiram Eldar, Feb 28 2025

Keywords

• nonn
• base

Comments

Are there 6 consecutive integers that are all terms in A381581?

Examples

			57744971 is a term since A291711(57744971) = 17 divides 57744971, A291711(57744972) = 18 divides 57744972, A291711(57744973) = 13 divides 57744973, A291711(57744974) = 14 divides 57744974, and A291711(57744975) = 15 divides 57744975.
		

Links

• Amiram Eldar, Table of n, a(n) for n = 1..130

Crossrefs

Cf. A291711.

Subsequence of A381581, A381582, A381583 and A381584.

Similar sequences: A330928, A334373, A364220, A364383.

Programs

PARI

mx = 20; fvec = vector(mx, i, fibonacci(2*i)); f(n) = if(n <= mx, fvec[n], fibonacci(2*n));
is1(n) = {my(s = 0, m = n, k); while(m > 0, k = 1; while(m > f(k), k++); if(m < f(k), k--); if(m >= 2*f(k), s += 2; m -= 2*f(k), s++; m -= f(k))); !(n % s);}
list(lim) = {my(q1 = is1(1), q2 = is1(2), q3 = is1(3), q4 = is1(4), s5); for(k = 5, lim, q5 = is1(k); if(q1 && q2 && q3 && q4 && q5, print1(k-4, ", ")); q1 = q2; q2 = q3; q3 = q4; q4 = q5);}