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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A383743 a(n) is the smallest prime not yet in the sequence that satisfies the following: for some pair of different digits i and j in a(n-1), i preceding j (from left to right), j precedes i in a(n). Leading 0s are not allowed; a(1)=13. See Comments for details.

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%I A383743 #21 Jun 15 2025 22:53:54
%S A383743 13,31,103,101,107,71,17,271,127,211,1021,109,191,19,491,139,131,113,
%T A383743 311,137,73,37,173,307,373,317,163,61,167,461,149,41,1049,241,421,
%U A383743 1123,251,151,157,521,257,523,353,53,359,193,239,293,349,43,347,431
%N A383743 a(n) is the smallest prime not yet in the sequence that satisfies the following: for some pair of different digits i and j in a(n-1), i preceding j (from left to right), j precedes i in a(n). Leading 0s are not allowed; a(1)=13. See Comments for details.
%C A383743 To obtain a(n), the digits i and j in a(n-1) are chosen among all possible pairs of different digits in a(n-1) so that they produce the smallest prime not yet in the sequence according to the precedence requirement in the definition.  Naturally, to obtain a(n+1), the process is repeated but now a different pair of digits k, l in a(n) may be chosen to produce a(n+1).
%C A383743 Note that it is enough that there exists a pair of digits i and j in a(n) that satisfy the precedence requirement; not every pair of such digits must satisfy the requirement in the case of multiple occurrences of such digits in a(n) (see examples).
%H A383743 Robert Israel, <a href="/A383743/b383743.txt">Table of n, a(n) for n = 1..10000</a>
%H A383743 Sean A. Irvine, <a href="https://github.com/archmageirvine/joeis/blob/master/src/irvine/oeis/a383/A383743.java">Java program</a> (github)
%e A383743 In a(2)=31 3 precedes 1, hence a(3)=103 since it is the smallest prime not yet in the sequence in which the digit 1 precedes 3.
%e A383743 In a(3)=103 1 precedes 0, hence a(4)=101 since it is the smallest prime not yet in the sequence in which the digit 0 precedes 1 (last two digits).
%e A383743 In a(10)=211 2 precedes 1, hence a(11)=1021 since it is the smallest prime not yet in the sequence in which the digit 1 precedes 2 (first and third digits).
%e A383743 In a(11)=1021 0 precedes 1 (second and fourth digits), hence a(12)=109 since it is the smallest prime not yet in the sequence in which the digit 1 precedes 0 (first and second digits).
%p A383743 P:= select(isprime,[seq(i,i=13 .. 1000,2)]):
%p A383743 g:= proc(n) local L, R,i,j;
%p A383743    L:= convert(n,base,10);
%p A383743    R:= select(t -> t[2] <> t[1], {seq(seq([L[i],L[j]],j=1..i-1),i=1..nops(L))});
%p A383743 end proc:
%p A383743 R:= 13: r:= 13: Cands:= subsop(1=NULL,P):
%p A383743 do qr:= map(t -> [t[2],t[1]],g(r)): found:= false;
%p A383743    for i from 1 to nops(Cands) do
%p A383743      if g(Cands[i]) intersect qr <> {} then
%p A383743        r:= Cands[i]; R:= R,r; Cands:= subsop(i=NULL,Cands); found:= true; break
%p A383743      fi
%p A383743    od;
%p A383743 until not found:
%p A383743 R; # _Robert Israel_, Jun 09 2025
%Y A383743 Cf. A107801, A381130.
%K A383743 nonn,base
%O A383743 1,1
%A A383743 _Enrique Navarrete_, May 08 2025