A384052 The number of integers k from 1 to n such that the greatest divisor of k that is a unitary divisor of n is a square.
1, 1, 2, 4, 4, 2, 6, 7, 9, 4, 10, 8, 12, 6, 8, 16, 16, 9, 18, 16, 12, 10, 22, 14, 25, 12, 26, 24, 28, 8, 30, 31, 20, 16, 24, 36, 36, 18, 24, 28, 40, 12, 42, 40, 36, 22, 46, 32, 49, 25, 32, 48, 52, 26, 40, 42, 36, 28, 58, 32, 60, 30, 54, 64, 48, 20, 66, 64, 44
Offset: 1
Links
- Amiram Eldar, Table of n, a(n) for n = 1..10000
Crossrefs
Unitary analog of A206369.
The number of integers k from 1 to n such that the greatest divisor of k that is a unitary divisor of n is: A047994 (1), A384048 (squarefree), A384049 (cubefree), A384050 (powerful), A384051 (cubefull), this sequence (square), A384053 (cube), A384054 (exponentially odd), A384055 (odd), A384056 (power of 2), A384057 (3-smooth), A384058 (5-rough).
Programs
-
Mathematica
f[p_, e_] := p^e - If[OddQ[e], 1, 0]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a,100]
-
PARI
a(n) = {my(f = factor(n)); prod(i = 1, #f~, f[i,1]^f[i,2] - if(f[i,2]%2, 1, 0));}
Formula
Multiplicative with a(p^e) = p^e-1 if e is odd, and p^e if e is even.
Dirichlet g.f.: zeta(s-1) * zeta(2*s) * Product_{p prime} (1 - 1/p^s - 1/p^(2*s) + 1/p^(2*s-1)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = zeta(4) * Product_{p prime} (1 - 1/p^2 + 1/p^3 - 1/p^4) = 0.74061963657217328604... .