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A384661 Solution of the complementary equation b(n)=a(a(n))+a(n)+2 with a(1)=1; this is the sequence a(n).

%I A384661 #8 Jun 16 2025 00:00:14
%S A384661 1,2,3,5,7,9,10,11,12,13,15,16,17,18,20,21,22,24,26,27,29,31,33,34,35,
%T A384661 36,38,40,42,43,45,46,47,48,50,51,53,54,56,57,58,59,61,62,63,65,66,68,
%U A384661 69,70,71,72,74,75,76,77,79,80,81,83,85,86,88,90,91,92
%N A384661 Solution of the complementary equation b(n)=a(a(n))+a(n)+2 with a(1)=1; this is the sequence a(n).
%C A384661 Sequence b is A384662.
%H A384661 Clark Kimberling, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL10/Kimberling/kimberling26.html">Complementary equations</a>, J. Int. Seq. Article 07.1.4 (2007), 1-13.
%e A384661 b(1) = a(a(1))+a(1)+2 = 1+1+2 = 4;
%e A384661 b(2) = a(a(2))+a(2)+2 = 2+2+2 = 6;
%e A384661 b(3) = a(a(3))+a(3)+2 = 3+3+2 = 8;
%e A384661 b(4) = a(a(4))+a(4)+2 = 5+7+2 = 14.
%Y A384661 Cf. A136497, A136499, A136500, A384662, A384663, A384664.
%K A384661 nonn
%O A384661 1,2
%A A384661 _Clark Kimberling_, Jun 06 2025