A384662 Solution of the complementary equation b(n)=a(a(n))+a(n)+2 with a(1)=1; this is the sequence b.

4, 6, 8, 14, 19, 23, 25, 28, 30, 32, 37, 39, 41, 44, 49, 52, 55, 60, 64, 67, 73, 78, 82, 84, 87, 89, 94, 99, 103, 106, 110, 113, 115, 118, 122, 124, 129, 131, 135, 138, 140, 142, 148, 150, 153, 158, 160, 165, 167, 169, 171, 174, 178, 181, 183, 186, 190, 193

Offset: 1

Author

Clark Kimberling, Jun 09 2025

Keywords

• nonn

Comments

Sequence a is A384661.

Examples

			b(1) = a(a(1))+a(1)+2 = 1+1+2 = 4;
b(2) = a(a(2))+a(2)+2 = 2+2+2 = 6;
b(3) = a(a(3))+a(3)+2 = 3+3+2 = 8;
b(4) = a(a(4))+a(4)+2 = 5+7+2 = 14.
		

Links

• Clark Kimberling, Complementary equations, J. Int. Seq. Article 07.1.4 (2007), 1-13.

Crossrefs

Cf. A136498, A136499, A136500, A384661, A384663, A384664.

Formula

{b(n)-b(n-1) : n>=2} = {2, 3, 4, 5, 6}.