A384664 Solution of the complementary equation b(n)=a(a(n))+a(n)+3 with a(1)=1; this is the sequence b. Sequence a is A384663.

5, 7, 9, 11, 17, 23, 27, 31, 34, 36, 38, 40, 45, 47, 49, 52, 54, 59, 61, 64, 70, 73, 75, 79, 82, 88, 93, 98, 102, 105, 108, 110, 115, 119, 124, 126, 132, 136, 139, 141, 144, 148, 152, 155, 159, 161, 164, 166, 168, 173, 175, 180, 185, 187, 190, 195, 197, 202

Offset: 1

Author

Clark Kimberling, Jun 16 2025

Keywords

• nonn

Examples

			b(1) = a(a(1))+a(1)+3 = 1+1+3 = 5;
b(2) = a(a(2))+a(2)+3 = 2+2+3 = 7;
b(3) = a(a(3))+a(3)+3 = 3+3+3 = 9;
b(4) = a(a(4))+a(4)+3 = 4+4+3 = 11;
b(5) = a(a(5))+a(5)+3 = 6+8+3 = 17.
		

Links

• Clark Kimberling, Complementary equations, J. Int. Seq. Article 07.1.4 (2007), 1-13.

Crossrefs

Cf. A136499, A136500, A384661, A384662, A384663.

Formula

{b(n)-b(n-1) : n>=2} = {2, 3, 4, 5, 6}.