cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A385433 a(n) is the 2-adic valuation of A027856(n).

Original entry on oeis.org

2, 1, 2, 1, 3, 2, 6, 4, 7, 5, 6, 3, 18, 12, 2, 18, 21, 24, 27, 30, 33, 43, 32, 36, 11, 31, 43, 32, 50, 63, 66, 79, 99, 57, 82, 148, 63, 56, 211, 275, 287, 90, 148, 298, 160, 363, 134, 49, 529, 264, 960, 541, 988, 1015, 1440, 1295, 979, 258, 637, 2320, 1036, 2815, 1063, 180, 888
Offset: 1

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Author

Ken Clements, Jul 31 2025

Keywords

Comments

These are the exponents, i, of the prime factor 2 of the A027856 numbers m = 2^i * 3^j where m is the average of twin primes. After the second term, all sums of i+j are odd because even sums (where j>0) make either m-1 or m+1 divisible by 5, which precludes twin primes except for the case of 6, where m-1 is divisible by 5, but 5 is the only number divisible by 5 that is also prime.

Examples

			a(1) = 2 because A027856(1) = 4 = 2^2 * 3^0
a(2) = 1 because A027856(2) = 6 = 2^1 * 3^1
a(3) = 2 because A027856(3) = 12 = 2^2 * 3^1
a(4) = 1 because A027856(4) = 18 = 2^1 * 3^2
a(5) = 3 because A027856(5) = 72 = 2^3 * 3^2
		

Crossrefs

Programs

  • Mathematica
    seq[max_] := IntegerExponent[Select[Sort[Flatten[Table[2^i*3^j, {i, 1, Floor[Log2[max]]}, {j, 0, Floor[Log[3, max/2^i]]}]]], And @@ PrimeQ[# + {-1, 1}] &], 2]; seq[10^250] (* Amiram Eldar, Aug 01 2025 *)
  • Python
    from math import log10
    from gmpy2 import is_prime
    l2, l3 = log10(2), log10(3)
    upto_digits = 200
    sum_limit = 2 + int((upto_digits - l3)/l2)
    def TP_pi_2_upto_sum(limit): # Search all partitions up to the given exponent sum.
        unsorted_result = [(2, log10(4)), (1, log10(6))]
        for exponent_sum in range(3, limit+1, 2):
            for i in range(1, exponent_sum):
                j = exponent_sum - i
                log_N = i*l2 + j*l3
                if log_N <= upto_digits:
                    N = 2**i * 3**j
                    if is_prime(N-1) and is_prime(N+1):
                         unsorted_result.append((i, log_N))
        sorted_result = sorted(unsorted_result, key=lambda x: x[1])
        return sorted_result
    print([i for i, _ in TP_pi_2_upto_sum(sum_limit) ])

A386730 a(n) is the 3-adic valuation of A027856(n).

Original entry on oeis.org

0, 1, 1, 2, 2, 3, 1, 3, 2, 4, 7, 10, 1, 5, 15, 5, 4, 5, 4, 7, 8, 2, 9, 7, 24, 12, 8, 15, 9, 2, 25, 20, 10, 64, 63, 27, 88, 99, 2, 16, 10, 169, 135, 51, 141, 52, 231, 320, 44, 419, 143, 476, 207, 332, 97, 324, 738, 1493, 1320, 333, 1167, 188, 1440, 2251, 2033
Offset: 1

Views

Author

Ken Clements, Jul 31 2025

Keywords

Comments

These are the exponents, j, of the prime factor 3 of the A027856 numbers m = 2^i * 3^j where m is the average of twin primes. Except for the first term, all are greater than zero because all other A027856 numbers have both 2 and 3 as prime factors. After the second term, all sums of i+j are odd because even sums make either m-1 or m+1 divisible by 5, which precludes twin primes except for the case of 6, where m-1 is divisible by 5, but 5 is the only number divisible by 5 that is also prime.

Examples

			a(1) = 0 because A027856(1) = 4 = 2^2 * 3^0
a(2) = 1 because A027856(2) = 6 = 2^1 * 3^1
a(3) = 1 because A027856(3) = 12 = 2^2 * 3^1
a(4) = 2 because A027856(4) = 18 = 2^1 * 3^2
a(5) = 2 because A027856(5) = 72 = 2^3 * 3^2
		

Crossrefs

Programs

  • Mathematica
    seq[max_] := IntegerExponent[Select[Sort[Flatten[Table[2^i*3^j, {i, 1, Floor[Log2[max]]}, {j, 0, Floor[Log[3, max/2^i]]}]]], And @@ PrimeQ[# + {-1, 1}] &], 3]; seq[10^250] (* Amiram Eldar, Aug 01 2025 *)
  • Python
    from math import log10
    from gmpy2 import is_prime
    l2, l3 = log10(2), log10(3)
    upto_digits = 200
    sum_limit = 2 + int((upto_digits - l3)/l2)
    def TP_pi_2_upto_sum(limit): # Search all partitions up to the given exponent sum.
        unsorted_result = [(0, log10(4)), (1, log10(6))]
        for exponent_sum in range(3, limit+1, 2):
            for i in range(1, exponent_sum):
                j = exponent_sum - i
                log_N = i*l2 + j*l3
                if log_N <= upto_digits:
                    N = 2**i * 3**j
                    if is_prime(N-1) and is_prime(N+1):
                         unsorted_result.append((j, log_N))
        sorted_result = sorted(unsorted_result, key=lambda x: x[1])
        return sorted_result
    print([j for j, _ in TP_pi_2_upto_sum(sum_limit) ])
Showing 1-2 of 2 results.