A056183 Sum of a(n) terms of 1/k^(6/7) first exceeds n.
1, 2, 4, 8, 16, 31, 56, 96, 158, 253, 393, 594, 878, 1271, 1806, 2523, 3472, 4711, 6312, 8359, 10949, 14199, 18243, 23237, 29360, 36816, 45841, 56698, 69689, 85152, 103467, 125060, 150406, 180034, 214529, 254542, 300788, 354056, 415215, 485213
Offset: 0
Keywords
Examples
For example, a(4) = 16 since Sum_{k=1..16} 1/k^(6/7) = 4.014698427... > 4, whereas Sum_{k=1..15} 1/k^(6/7) = 3.921823784... < 4.
Programs
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Mathematica
s = 0; k = 1; Do[ While[ s <= n, s = s + N[ 1/k^(7/8), 24 ]; k++ ]; Print[ k - 1 ], {n, 1, 40} ]